For this case what you should do is use the following trigonometric relationship:
tan (x) = C.O / C.A
Where
x: angle
C.O: opposite leg
C.A: adjoining catheto
Substituting the values we have:
tan (60) = long / short
tan (60) = long / 2
long = 2 * tan (60)
long = 3.46
Answer:
long = 3.46
Just have a very grate day
(5)(5)(5)(5)(5)(5)(5)(5)(5)(5)(5)
5^11
That is two of the three but I'm not quite sure if there is a third.
Answer:
(in attachment)
Step-by-step explanation:
you can find the points by inputting the x-values into the equation to solve for the y-values, then connecting the plotted points to create the line.
When x=-4
y=1/2(-4)
y=-2
(-4,-2)
Repeat for all values.