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malfutka [58]
3 years ago
7

A classic counting problem is to determine the number of different ways that the letters of "success" can be arranged. Find that

number
Mathematics
2 answers:
arlik [135]3 years ago
7 0

Answer:420 ways

Step-by-step explanation:

Success

The total =7!

S: 3!

C:2!

Permutation: 7!/(3!2!)

: 5040/(6×2)

The arrangement will be 420ways

Drupady [299]3 years ago
3 0

Answer: 420 ways

Step-by-step explanation:

Given the word "success"

It consists of :

3 letter "s" = 3!

2 letter "c" = 2!

And a total of 7 letters. = 7!

The number of ways that the letters can be arranged can be given as;

N = 7!/(3!)(2!)

N = 7!/12 = 420 ways

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Solving Square Root Worksheet (x - k)^2 Part 3
erastova [34]

Answer:

7. x = -2 +/- 4i\sqrt{5}

8. x = 2 or x = 6

9. x = -2 +/- \frac{\sqrt{26} }{2} i

10. t = -3 +/- \sqrt{35}

Step-by-step explanation:

7. Subtract 320 from both sides: 4(x + 2)^2 = -320

Divide by 4: (x + 2)^2 = -80

Square root both sides: x + 2 = +/- \sqrt{-80}. We need to add the imaginary i to this: +/- \sqrt{-80} = +/- i\sqrt{80} = +/- 4i\sqrt{5}

Subtract 2 from both sides: x = -2 +/- 4i\sqrt{5}

8. Add 18 to both sides: 7(x - 4)^2 = 28

Divide by 7: (x - 4)^2 = 4

Square root both sides: x - 4 = +/- 2

Add 4 to both sides: x = 4 +/- 2  ⇒  x = 2 or x = 6

9. Add 5 to both sides: -2(x + 2)^2 = 13

Divide by -2: (x + 2)^2 = -13/2

Square root both sides: x + 2 = +/- \sqrt{-13/2}. We again need i: +/- \sqrt{-13/2} = +/- i\sqrt{13/2} = +/- \frac{\sqrt{26} }{2} i

Subtract 2 from both sides: x = -2 +/- \frac{\sqrt{26} }{2} i

10. Multiply by 5 on both sides: (t + 3)^2 = 35

Square root both sides: t + 3 = +/- \sqrt{35}

Subtract 3: t = -3 +/- \sqrt{35}

Hope this helps!

3 0
4 years ago
Read 2 more answers
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Annfiidsidnnw I didn’t have a time I was going on with my dad so he didn’t have to work so he was just asking if he could do anything else and he said I was just

4 0
2 years ago
I need help answering
german

6t - 20 - 32u

6(6) - 20 - 32(1/4)

36 - 20 - 8

36 - 20 = 16 - 8 ⇒8

The final answer is 8.

4 0
3 years ago
A car travels a distance on a road of 12.42 miles at a slope of 6.4%. The car has a maximum speed of 203 mph. Assume the car wil
Neko [114]

Answer:

4 mins 31 seconds

Step-by-step explanation:

Maximum speed is 203 mph equivalent to

203*\frac {5280}{3600}=297.73 ft/s

Time taken to attain maximum speed, t=\frac {v}{a} where v is velocity and a is acceleration hence

t=\frac {297.73}{2.93}=101.6155 s

The distance traveled when at top speed

d=\frac {v^{2}}{2a}=\frac {(297.73)^{2}}{2*2.93}=15127.16 \approx 15127.2 ft

Total distance is provided as 12.42 miles converted to ft is 12.42*5280=65577.6 ft

Total distance-distance moved to attain maximum speed will be

65577.6 ft-15127.2 ft=50450.44 ft

Time taken during maximum speed

t=\frac {50450.44}{297.73}=169.45 s

Total time=101.6155 s+169.45 s=271.06 s

271.06/60=4 mins 31 seconds

8 0
3 years ago
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PLEASE HELP!!! URGENT
fomenos
29.1 bc the hypotenuse is always the longest side
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