Answer:
1.) 48
2.) 65
3.) 36
Step-by-step explanation:
1.) If the equation is 6(x-4) and x = 12, then all we have to do is plug in the value of x. When we plug in, all we do is substitute 12 for x because they mentioned in the question that x = 12. So, we end up getting 6(12 - 4). After solving this, we get 48.
2.) This problem is a lot like the last problem. All we need to do is substitute /plug in the values of x and y into the equation, to get 4(4^2) - 35/7 - (8 + 14). After solving, we get 65.
3.) . This problem, once again, is also a lot like the last problems. We need to substitute the value of x into the equation 8x+12. Since we know from the problem that x is 3, all we have to do is 8 * 3 + 12.
Answer:
the domain of the function f(x) is 
the range of the function f(x) is 
Step-by-step explanation:
Consider the parent function 
The domain og this function is 
the range of this function is 
The function 
is translated function 
7 units to the right and 9 units up, so
the domain of the function f(x) is
the range of the function f(x) is
Answer:
14b
Step-by-step explanation:
Here, we want to get the greatest common factor of the two terms
The greatest common factor can be obtained by finding the expression that factor the given expression
We have this as;
14b(2a + 3)
So the greatest common factor is 14b
Answer: No she cannot cover it
Step-by-step explanation:
1yd² = 1296in²
16 x 11 x 9 = 1584in²
1296in² < 1584in²
The distance between Car A and car B,When Car A crosses the start line is:
distance =speed car B* time
distance=(15 m/s)(3 s)=45 m
Distance traveled by car A =x, (when the car B is at the same distance from the start line)
time of car A=t
x=10 m/st ⇒ x=10t (1)
Distance traveled by car B=x
time of car B=t-3
x=15(t-3) (2)
With the equations (1) and (2) we make a system of equations:
x=10t
x=15(t-3)
We solve this system of equations:
10t=15(t-3)
10t=15t-45
-5t=-45
t=-45 / -5
t=9
t-3=9-3=6
x=10 t=10 (9)=90
Answer: The time would be 9 seconds for Car A and 6 seconds for car B and the distance would be 90 meters.
