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3 years ago

NO ONE KNOWS THIS ANSWER?

Mathematics

1 answer:

LenaWriter [7]3 years ago

6 0

Answer:

Their intercepts are unique.

Explanation:

$\displaystyle x^3 - 24x^2 + 192x - 508 = (x - 8)^3 + 4$

This graph's x-intercept is located at approximately [6,41259894, 0], and the y-intercept located at [0, −508].

$\displaystyle g(x) = x^3$

The parent graph here, has both an x-intercept and y-intercept located at the origin.

I am joyous to assist you anytime.

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Simplify: –3(x – 5) – 8(y + 2) + (–3)(6 – 4b)

Paha777 [63]

-3 (x - 5) - 8 (y + 2) + (-3) (6 - 4b)

First, simplify your brackets. / Your problem should look like: -3 (x - 5) - 8 (y + 2) + -3 (6 - 4b)
Second, simplify. / Your problem should look like: -3 (x - 5) - 8 (y + 2) - 3 (b - 4b)
Third, expand your problem. / Your problem should look like: -3x + 15 - 8y - 16 - 18 + 12b
Fourth, simplify. / Your problem should look like: -3x - 8y + 12b - 19

Answer: -3x - 8y + 12b - 19 (D)

3 0

3 years ago

Read 2 more answers

5/6 divided by 1 and 1/2?

Tema [17]

Answer:

5/9

Step-by-step explanation:

(5/6)/1 1/2

5/9

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6 0

3 years ago

To estimate the mean height μ of male students on your campus,you will measure an SRS of students. You know from government data

nexus9112 [7]

Answer:

a) $\sigma = 0.167$

b) We need a sample of at least 282 young men.

Step-by-step explanation:

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by

$Z = \frac{X - \mu}{\sigma}$

This Zscore is how many standard deviations the value of the measure X is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

(a) What standard deviation must x have so that 99.7% of allsamples give an x within one-half inch of μ?

To solve this problem, we use the 68-95-99.7 rule. This rule states that:

68% of the measures are within 1 standard deviation of the mean.

95% of the measures are within 2 standard deviations of the mean.

99.7% of the measures are within 3 standard deviations of the mean.

In this problem, we want 99.7% of all samples give X within one-half inch of $\mu$ . So $X - \mu = 0.5$ must have $Z = 3$ and $X - \mu = -0.5$ must have $Z = -3$ .

$Z = \frac{X - \mu}{\sigma}$

$3 = \frac{0.5}{\sigma}$

$3\sigma = 0.5$

$\sigma = \frac{0.5}{3}$

$\sigma = 0.167$

(b) How large an SRS do you need to reduce the standard deviationof x to the value you found in part (a)?

You know from government data that heights of young men are approximately Normal with standard deviation about 2.8 inches. This means that $\sigma = 2.8$