The domain and range of
the function f(t)=sec[((pi)t)/4] are the following:
<span>Domain: All the real
numbers except t = 2 + 4k, where k is an integer. </span>
Range: (-∞, -1] U
[1, ∞)
I am hoping that these answers
have satisfied your queries and it will be able to help you in your endeavors, and
if you would like, feel free to ask another question.
3/3-1/3= 2/3 of the glasses
Answer:
(f - g)(2) = 11
Step-by-step explanation:
f(x) = 3² + 1
g(x) = 1 - x
(f - g)(2) = f(2) - g(2)
f(2) = 9 + 1 = 10
g(2) = 1 - 2 = -1
10 - (-1) = 10 + 1 = 11
(f - g)(2) = 11
Answer:
V = $3.50t + $90.5....
Step-by-step explanation:
V(t) is a function of t that expresses the value in year 2000+t.
We know that the increase is $3.50 times t.
So,
V(t) = $3.50t + c
where c is the constant.
V(15) = $3.50 (15) + c = $143 [t=15 as mentioned in the question]
and therefore
c = $143 - $3.50 (15)
c= $143 - $52.50
c= $90.5
Now we got the value of c. We can write the equation as
V = $3.50t + $90.5....
