Answer:
![R = 0.0000498 \frac{KJ}{ m m^3}=0.0000498 \frac{KJ}{m^4}=4.98x10^{-5}\frac{KJ}{m^4}](https://tex.z-dn.net/?f=%20R%20%3D%200.0000498%20%5Cfrac%7BKJ%7D%7B%20m%20m%5E3%7D%3D0.0000498%20%5Cfrac%7BKJ%7D%7Bm%5E4%7D%3D4.98x10%5E%7B-5%7D%5Cfrac%7BKJ%7D%7Bm%5E4%7D)
Step-by-step explanation:
For this case we have the following value:
![R = 0.0498 \frac{Kpa}{Km}](https://tex.z-dn.net/?f=%20R%20%3D%200.0498%20%5Cfrac%7BKpa%7D%7BKm%7D)
We can convert this first to
like this:
![R=0.0498 \frac{Kpa}{Km} *\frac{1km}{1000m}=0.0000498 \frac{Kpa}{m}](https://tex.z-dn.net/?f=%20R%3D0.0498%20%5Cfrac%7BKpa%7D%7BKm%7D%20%2A%5Cfrac%7B1km%7D%7B1000m%7D%3D0.0000498%20%5Cfrac%7BKpa%7D%7Bm%7D)
Now we use the fact the the pressure is defined as
, whre P is the pressure, F the force and A the area, so then
and then we can replace this:
![R=0.0000498 \frac{KN}{m^3}](https://tex.z-dn.net/?f=%20R%3D0.0000498%20%5Cfrac%7BKN%7D%7Bm%5E3%7D)
Now from definition of work we know that
where W is the work, F the force and d the distance, so then is equivalent ![KN =\frac{KJ}{m}](https://tex.z-dn.net/?f=%20KN%20%3D%5Cfrac%7BKJ%7D%7Bm%7D)
And if we replace this into the equation we got:
![R = 0.0000498 \frac{KJ}{ m m^3}=0.0000498 \frac{KJ}{m^4}=4.98x10^{-5}\frac{KJ}{m^4}](https://tex.z-dn.net/?f=%20R%20%3D%200.0000498%20%5Cfrac%7BKJ%7D%7B%20m%20m%5E3%7D%3D0.0000498%20%5Cfrac%7BKJ%7D%7Bm%5E4%7D%3D4.98x10%5E%7B-5%7D%5Cfrac%7BKJ%7D%7Bm%5E4%7D)
Answer:
113-2t√17
Step-by-step explanation:
Answer:
E
Step-by-step explanation:
because you divide 1 3/4 (1.75) over 1/5 (.2) to get 8 3/4 (8.75)
Answer: Line R and Line P are perpendicular because they intersect at a point and create a pair of equal angles.
Step-by-step explanation:
I think it would be around -8.
Hope it helps!