<h3><u>1. Find the permutation of the word LOVE taken 2 letters at a time.</u></h3>
<h2><u>ANSWER</u><u> </u><u>IS</u><u> </u><u>C.12</u></h2>
<h2>--------------------------------------------------------------------------------</h2>
<h3><u>2. If 3 girls enter a jeepney in which there are 7 vacant seats, how many ways are there for them to be seated?</u></h3>
<h2><u>ANSWER</u><u> </u><u>IS</u><u> </u><u>B.210</u></h2>
<h2>--------------------------------------------------------------------------------</h2>
<h3><u>3. How many combinations can be made from the letters of the word MOTHER taken 4 at a time.</u></h3>
<h2><u>ANSWER</u><u> </u><u>IS</u><u> </u><u>A.15</u></h2>
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<h3>→XxKim02xX</h3>
Answer:
1. P(S) = 373/580
2. P(S|A) = 53/116
3. P(S|Pa) = 481/580
Step-by-step explanation:
Given
---------------------Sale ----- No Sale-----Total
Aggressive ----265 --------315 ----------580
Passive ----------481 ---------99 -----------580
Total --------------746---------414------------1160
A = aggressive approach,
Pa = passive approach,
S = sale,
N= no sale.
(a) Computing P(S)
This is calculated as the division of customers that participated in sales by total customers
Customers that participated in sales = 265 + 481 = 746
Total Customers = 1160
P(S) = 746/1160
P(S) = 373/580
b.
P(S|A) means that the probability that a sales occur given that the aggressive method was used.
To solve this, we check the cell where Sales and Aggressive intersect
The cell element = 265
Total = 580
P(S|A) = 265/580
P(S|A) = 265/580
P(S|A) = 53/116
c.
P(S|Pa) means that the probability that a sales occur given that the passive method was used.
To solve this, we check the cell where Sales and Passive intersect
The cell element = 481
Total = 580
P(S|Pa) = 481/580
The ordered pair (2,0) represents the equation 3y+4x= 8
