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Dahasolnce [82]
3 years ago
9

Jon's coin collection consists of quarters, dimes and nickels. If the ratio of quarters to dimes is 5:2, and the ratio of dimes

to nickels is 3:4,what is the ratio of quarters to nickels?
Mathematics
1 answer:
Margarita [4]3 years ago
8 0

Answer:

The ratio of quarters to nickels is:

  • <u>15:8</u>

Step-by-step explanation:

To solve the exercise, you must first consider how big is the ratio of each one to the other, when it is mentioned that the ratio of quarters to dimes is 5:2 it means that for every 5 quarters, Jon has 2 dimes, for the more quarters there are with respect to the dimes, we simply divide the larger value by the smaller:

  • 5/2 = 2.5

Thus, we know that there are 2.5 more quarters than dimes. Now the following proportion: the ratio of dimes to nickels is 3:4, which means that for every 3 dimes there are 4 nickels, as the nickels are greater in quantity, we are going to see how many times they are greater in proportion than the dimes making again a division of the major over the minor:

  • 4/3 = 1.33333333333 (<em>we are going to use the fractional number so as not to lose decimals</em>).

As we can see, the nickels are a little more than 1 with respect to the dimes, now we are going to create two formulas with those values:

  • <em>q = 2.5d </em>
  • <em>n = 4/3 d</em>

Where:

  • q = quarters
  • d = dimes
  • n = nickels

As you see. We only express the calculated proportions, at first glance you can identify that the number of quarters is greater, but to know how much greater with respect to nickels we are going to divide the two values ​​that accompany "d" in the formulas:

  • <u>2.5 / (4/3) = 15/8</u>

If we express it in ratio as it is in the exercise, we obtain:

  • <u>15:8</u>

So, <u>15:8 is the ratio of quarters to nickels</u>, <em>which means that for every 15 quarters, jon has 8 nickels.</em>

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10.45

Step-by-step explanation:

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A stadium has 50,000 seats. Seats sell for $25 in section A, $20 in section B, and $15 in section C. The number of seats in sect
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Answers:

section A = 25,000 seats

section B = 14,200 seats

section C = 10,800 seats

Your teacher may want you to leave out the commas from each number.

=============================================================

Work Shown:

  • A = number of seats in section A
  • B = number of seats in section B
  • C = number of seats in section C

A = B+C

A+B+C = 50,000

B+C+B+C = 50,000

2(B+C) = 50,000

B+C = 50,000/2

B+C = 25,000

C = 25,000 - B

25A + 20B + 15C = 1,071,000

25(B+C) + 20B + 15C = 1,071,000

25(25,000) + 20B + 15(25,000 - B) = 1,071,000

625,000 + 20B + 375,000 - 15B = 1,071,000

1,000,000 + 5B = 1,071,000

5B = 1,071,000 - 1,000,000

5B = 71,000

B = (71,000)/5

B = 14,200 is the number of seats in section B

C = 25,000 - B

C = 25,000 - 14,200

C = 10,800 is the number of seats in section C

A = B+C

A = 14,200 + 10,800

A = 25,000 is the number of seats in section A

--------------

Check:

A+B+C = 25,000+14,200+10,800 = 50,000

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And She can eat 12 or more grams of proteins

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So, we can write an inequality equation, that describes the given situation in the problem.

i.e. 2x + 3y ≥ 12  or 12 ≤ 2x + 3y

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