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3 years ago

Write an algebraic equation for the following sentence explaining each step of your reasoning:

Mathematics

1 answer:

inysia [295]3 years ago

6 0

2n-12=9+n you rearrange the variables to what the equation says

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If discriminant (b^2 -4ac>0) how many real solutions

MaRussiya [10]

Answer:

If Discriminant, $b^{2} -4ac >0$

Then it has Two Real Solutions.

Step-by-step explanation:

To Find:

If discriminant (b^2 -4ac>0) how many real solutions

Solution:

Consider a Quadratic Equation in General Form as

$ax^{2} +bx+c=0$

then,

$b^{2} -4ac$ is called as Discriminant.

So,

If Discriminant, $b^{2} -4ac >0$

Then it has Two Real Solutions.

If Discriminant, $b^{2} -4ac < 0$

Then it has Two Imaginary Solutions.

If Discriminant, $b^{2} -4ac=0$

Then it has Two Equal and Real Solutions.

4 0

2 years ago

If the circumference of two circle are in the ratio 2:3, then their areas are in the ratio of

maxonik [38]

Answer:

4:9

Step-by-step explanation:

To take the scale factor from distance to area, we square it

2:3 distance

Square each term

2^2 : 3^2 area

4:9

6 0

2 years ago

Select the correct answer.<br> Which of these is not a key feature of the function

kkurt [141]

Answer:

what is the answer to this question?

Step-by-step explanation:

7 0

3 years ago

Pls someone answer pls :)

Goshia [24]

Answer:

(-x-2) (-2x -3)=0

=>[-(x +2)] [-(2x+3)]=0

=>(x + 2)(2x +3)=0

=>x =-2 or,x=-3/2

smaller x=-2

larger x =-3/2

3 0

3 years ago

Read 2 more answers

Solve for z<br> -p(d+z) = -2z+59−p(d+z)=−2z+59

alexira [117]

$-p(d+z)=-2z+59\qquad\text{use distributive property}\\\\-pd-pz=-2z+59\qquad\text{add pd to both sides}\\\\-pz=-2z+pd+59\qquad\text{add 2z to both sides}\\\\2z-pz=pd+59\\\\z(2-p)=pd+59\qquad\text{divide both sides by}\ (2-p)\neq0\\\\\boxed{z=\dfrac{pd+59}{2-p}}$

6 0

2 years ago