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Shtirlitz [24]
3 years ago
12

28= Square root 2(9.8)h. H?

Mathematics
1 answer:
taurus [48]3 years ago
8 0

Answer:


Step-by-step explanation:


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5. If "h" is positive how does the parabola move? If negative?
Paul [167]

Answer: positive values for h translate the parabola to the right, negative values for h translate the parabola to the left

Step-by-step explanation: Note that the value for h is subtracted from x, and then this difference is squared. See that positive values for h translate the parabola to the right, negative values for h translate the parabola to the left

7 0
3 years ago
the sun shines on a flagpole, causing a shadow to be cast on the ground. the distance from the base of the pole to the tip of th
kobusy [5.1K]

Answer:

30.17feet high

Step-by-step explanation:

Given the following

the distance from the base of the pole to the tip of the shadow = 49feet (hypotenuse)

angle of elevation = 38°

Required

Height of the flagpole (opposite)

Using the SOH CAH TOA identity

Sin theta = opposite/hypotenuse

Sin 38 = H/49

H = 49sin38

H = 49(0.6157)

H = 30.17feet

Hence the flagpole is 30.17feet high

7 0
3 years ago
Select equivalent or not equivalent for each pair of expressions
marissa [1.9K]

Answer:

1: equivalent

2: equivalent

3: not equivalent

Step-by-step explanation:

for 1 & 2, you just switch the terms, but for 3, the 6z is not negative in the first expression, but it is in the second.

3 0
3 years ago
Help ASAP worth 20 points please help me
Savatey [412]

Answer:

What do you mean by a tap diagram?

Step-by-step explanation:

4 0
3 years ago
Please help: linear algebra problem. (Linear combinations)
DochEvi [55]

Answer:

\left[\begin{array}{ccc}5&7\\5&-8\\3&-9\end{array}\right] \left[\begin{array}{ccc}c\\d\end{array}\right] =\left[\begin{array}{ccc}-16\\3\\-15\end{array}\right]

This tells us that:

A=\left[\begin{array}{ccc}5&7\\5&-8\\3&-9\end{array}\right]

b=\left[\begin{array}{ccc}-16\\3\\-15\end{array}\right]

Step-by-step explanation:

So we are saying we have scalars, c and d, such that:

c\left[\begin{array}{ccc}5\\5\\ 3\end{array}\right]+d\left[\begin{array}{ccc}7\\-8\\-9\end{array}\right]=\left[\begin{array}{ccc}-16\\3\\-15\end{array}\right].

So we want to find a way to express this as:

Ax=b where x is the scalar vector, \left[\begin{array}{ccc}c\\d\end{array}\right].

So we can write this as:

\left[\begin{array}{ccc}5&7\\5&-8\\3&-9\end{array}\right] \left[\begin{array}{ccc}c\\d\end{array}\right] =\left[\begin{array}{ccc}-16\\3\\-15\end{array}\right]

3 0
3 years ago
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