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2 years ago

If a base of a rectangle is 36cm and the area is 845cm2 what is the height of the rectangle

Mathematics

1 answer:

sveta [45]2 years ago

8 0

$\sf~A=bh$

Plug in what we know:

$\sf845=36h$

Divide 36 to both sides:

$\sf~h\approx23.47$

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Each of the 10 students in the baking club made 2 chocolate cakes for a fundraiser they all used the same recipe, using C cups o

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Answer:

C / 20

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3 years ago

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2 years ago

Read 2 more answers

Need to find volume, step by step explanation pls

worty [1.4K]

Given:

A figure of combination of hemisphere, cylinder and cone.

Radius of hemisphere, cylinder and cone = 6 units.

Height of cylinder = 12 units

Slant height of cone = 10 units.

To find:

The volume of the given figure.

Solution:

Volume of hemisphere is:

$V_1=\dfrac{2}{3}\pi r^3$

Where, r is the radius of the hemisphere.

$V_1=\dfrac{2}{3}(3.14)(6)^3$

$V_1=\dfrac{6.28}{3}(216)$

$V_1=452.16$

Volume of cylinder is:

$V_2=\pi r^2h$

Where, r is the radius of the cylinder and h is the height of the cylinder.

$V_2=(3.14)(6)^2(12)$

$V_2=(3.14)(36)(12)$

$V_2=1356.48$

We know that,

$l^2=r^2+h^2$ [Pythagoras theorem]

Where, l is length, r is the radius and h is the height of the cone.

$(10)^2=(6)^2+h^2$

$100-36=h^2$

$\sqrt{64}=h$

$8=h$

Volume of cone is:

$V_3=\dfrac{1}{3}\pi r^2h$

Where, r is the radius of the cone and h is the height of the cone.

$V_3=\dfrac{1}{3}(3.14)(6)^2(8)$

$V_3=\dfrac{25.12}{3}(36)$

$V_3=301.44$

Now, the volume of the combined figure is:

$V=V_1+V_2+V_3$

$V=452.16+1356.48+301.44$

$V=2110.08$

Therefore, the volume of the given figure is 2110.08 cubic units.

7 0

2 years ago