Answer:
Step-by-step explanation:
For a. you are asked to evaluate f(0). This is a piecewise function with different domains for each piece of the function. You can only evaluate f(0) in the function that has a domain that allows 0 in it. In the first domain, it says
x < -3. 0 is not less than -3, so 0 is not in that domain, so you will not use that "piece" of the function to evaluate f(0).
In the next domain, it says that x is greater than or equal to -3 and less than 0. Again, 0 is not included in that domain, so we can't use that "piece" of the function to evaluate f(0).
The last domain says that x is greater than OR EQUAL TO 0, so this is where we evaluate f(0):
f(0) = -0 - 4 so
f(0) = -4
When we want to evaluate f(2), we follow the same rules. Find the piece of the function that allows 2 in its domain. That's the middle piece:
f(2) = 2(2) - 6 so
f(2) = -2
