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3 years ago

FYI I thank to everyone and give brainliest!!!!!!!!!

Mathematics

1 answer:

Kobotan [32]3 years ago

4 0

To find (f+g)(x), add the equations and simplify by combining like terms.

(x/2)-2+2x^2+x-3
2x^2+ (x/2) +x -5
2x^2 + (1/2)x+x -5
2x^2+ (3/2)x -5

Final answer: C

Remember that (x/2) is the same as (1/2)x. They both represent half of x.

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Need help. greatly appreciated

gizmo_the_mogwai [7]

1. It must be divisible by 2 and 3. It IS divisible by 2. it IS divisible by 3. No remainder.
2. Add the digits and see if the sum is divisible by 3. Apply this rule to both numbers. 3 is not a common factor.
3a. 639
3b. 1035
3c. 179

7 0

3 years ago

Find two consecutive integers whose sum is 373.

nadya68 [22]

Answer:

186 and 187

Step-by-step explanation:

Let n be the first integer.

Then n+1 is the next integer.

We are given their sum is 373.

n+(n+1)=373

Combine like terms:

2n+1=373

Subtract 1 on both sides:

2n=372

Divide both sides by 2:

n=186

So n+1=187.

187

+186

--------

373

4 0

3 years ago

Find the 22th term in the arithmetic sequence<br> 23,14,5,-4

Darya [45]

Answer:

-45

Step-by-step explanation: no explanation

3 0

3 years ago

What is the answer to this question because i do not know 5/12 x =1

Otrada [13]

Answer:

x=12/5

Step-by-step explanation:

x*5/12=1

x=1*12/5

x=12/5

3 0

2 years ago

Read 2 more answers

Someone plz help me with this

Phoenix [80]

Answer:

$5y^{6}\sqrt{2}$

Step-by-step explanation:

We want to simplify:

$\sqrt{50y^{12}}$

We rewrite as:

$\sqrt{2\times25 \times (y^{6})^2}$

We split the radical sign to obtain:

$\sqrt{25} \times \sqrt{(y^{6})^2} \times \sqrt{2}$

Simplify the square root for the perfect squares to get:

$5y^{6}\sqrt{2}$

Therefore the simplified form is: $5y^{6}\sqrt{2}$

8 0

3 years ago