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Bad White [126]
3 years ago
15

Write an equation in slope-intercept form of the line that passes through (−5, 19) and (5, 13)

Mathematics
1 answer:
kotykmax [81]3 years ago
6 0
13-19/5+5=-6/10=-3/5
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<span>To determine whether (−1,4) is a solution to the equation 3x+8y=29, substitute  ...-1... for x and ...4... and for y.


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Similarly, the second coordinate occupied by 4 represents y.


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Explain the steps you would take to write 36/10 as a decimal
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How can I factor 5x^2 + 26x - 24 = 0 using the completing the square method.
kifflom [539]
<h2><u>QUADRATIC EQUATION</u></h2>

<h2>\mathbb{ANSWER:}</h2>
  • \bold{x = 0.8 \: } \:  \sf \:  {\color{grey}or} \:  \:  \:  \bold{ x=  \frac{4}{5} } \\

  • \bold{x =  - 6}

— — — — — — — — — —

<h3>Step-by-step explanation:</h3>

<u>How can </u><u>we</u><u> factor 5x^2 + 26x - 24 = 0 using the completing the square </u><u>method?</u>

Let's solve your equation step-by-step.

\bold{Given \:  Equation: \color{brown} 5x²+26x-24=0}

First, add 24 to both sides.

  • \bold{5x²+26x-24 - \purple{ 24} = 0 +  \purple{24}}

  • \bold{ \implies \: 5x²+26x = 24 }

Since the coefficient of 5x² is 5, divide both sides by 5.

  • \bold{ \frac{5 {x}^{2} + 26x }{5} =  \frac{24}{5}  } \\

  • \bold{ \implies \:  {x}^{2} +  \frac{26}{5} x =  \frac{24}{5}  } \\

The coefficient of 26/5x is 26/5. So, let b=26/5.

Then we need to add (b/2)²=169/25 to both sides to complete the square.

Add 169/25 to both sides.

  • \bold{ {x}^{2} +  \frac{26}{5} x +  \frac{  \purple{169}}{ \purple{25}}=  \frac{24}{5}    +  \frac{ \purple{169}}{ \purple{25}} } \\

  • \bold{ \implies \:\bold{ {x}^{2} +  \frac{26}{5} x +  \frac{  169}{ {25}}=  \frac{289}{25}  } } \\

Factor the left side.

  • \bold{(x +  \frac{13}{5} ) {}^{2} =  \frac{289}{25}  } \\

Take square root.

  • \bold{x +  \frac{13}{5} = ±  \:  \sqrt{ \frac{289}{25}  }} \\

Then, add (-13)/5 to both sides.

  • \bold{x +  \frac{13}{5} +  \frac{\purple{ - 13} }{\purple{ 5}} = \frac{{ - 13} }{{ 5}} ± \:      \sqrt{ \frac{289}{25}}} \\

  • \bold{  \: x =  \frac{ - 13}{5} ± \sqrt{ \frac{289}{25} } } \\

  • \implies \: \underline{ \boxed{ \bold{   \frac{4}{5}  } \sf  \:  \: or \:  \:  \bold{ x =  - 6}}} \\

_______________❖_______________

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Step-by-step explanation:

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