First of all, when I do all the math on this, I get the coordinates for the max point to be (1/3, 14/27). But anyway, we need to find the derivative to see where those values fall in a table of intervals where the function is increasing or decreasing. The first derivative of the function is
![f'(x)=-3x^2-8x+3](https://tex.z-dn.net/?f=f%27%28x%29%3D-3x%5E2-8x%2B3)
. Set the derivative equal to 0 and factor to find the critical numbers.
![0=-3x^2-8x+3](https://tex.z-dn.net/?f=0%3D-3x%5E2-8x%2B3)
, so x = -3 and x = 1/3. We set up a table of intervals using those critical numbers, test a value within each interval, and the resulting sign, positive or negative, tells us where the function is increasing or decreasing. From there we will look at our points to determine which fall into the "decreasing" category. Our intervals will be -∞<x<-3, -3<x<1/3, 1/3<x<∞. In the first interval test -4. f'(-4)=-13; therefore, the function is decreasing on this interval. In the second interval test 0. f'(0)=3; therefore, the function is increasing on this interval. In the third interval test 1. f'(1)=-8; therefore, the function is decreasing on this interval. In order to determine where our points in question fall, look to the x value. The ones that fall into the "decreasing" category are (2, -18), (1, -2), and (-4, -12). The point (-3, -18) is already a min value.
Answer:
Step-by-step explanation:
Given that a bank representative studies compound interest, so she can better serve customers. She analyzes what happens when $2,000 earns interest several different ways at a rate of 2% for 3 years.
a) the interest if it is computed using simple interest. 12.00
=
dollars
b) the interest if it is compounded annually.
=
dollars
c) the interest if it is compounded semiannually
=![2000(1.06)^6 -2000\\= 837.04](https://tex.z-dn.net/?f=2000%281.06%29%5E6%20-2000%5C%5C%3D%20837.04)
d) the interest if it is compounded quarterly.
=![2000(1.03)^12 -2000\\= 851.52](https://tex.z-dn.net/?f=2000%281.03%29%5E12%20-2000%5C%5C%3D%20851.52)
e) the interest if it is compounded monthly.
=![2000(1.01)^24 -2000\\= 861.54](https://tex.z-dn.net/?f=2000%281.01%29%5E24%20-2000%5C%5C%3D%20861.54)
Answer:
greater than
Step-by-step explanation:
On a number line 160 is further to the right than 2 1/2
Answer:
what is tow more the the product of a number and 7 equal to?
Step-by-step explanation:
Answer:
Is it 44c^4 ? Because if it is below is my answer;
Step-by-step explanation:
2c^3 (c + 11)^2