Answer:
What does your digital footprint say about you?
Explanation:
Just follow the path from the end to the start, that's how I always get mazes.
Answer:
1. A high level algorithm for cooking a cheeseburger could be:
- Heat fry pan
- Cook one side of the hamburger
- Wait
- Turn hamburger upside down
- Put cheese over hamburger
- Wait
- Cut hamburger bread in half
- Put cooked hamburger inside bread
- End (eat)
2. A detailed algorithm for cooking a cheeseburger could be:
- Place fry pan over the stove heater
- Turn on heater (max temp)
- IF fry pan not hot: wait, else continue
- Place raw hamburger on fry pan
- IF hamburger not half cooked: Wait X time then go to line 5, else continue
- Turn hamburger upside down
- Put N slices of cheese over hamburger
- IF hamburger not fully cooked: Wait X time then go to line 8, else continue
- Turn off heater
- Cut hamburger bread in half horizontally
- Put cooked hamburger on one of the bread halves.
- Put second bread half on top of hamburger
- End (eat)
Explanation:
An algorithm is simply a list of steps to perform a defined action.
On 1, we described the most relevant steps to cook a simple cheeseburger.
Then on point 2, the same steps were taken and expanded with more detailed steps and conditions required to continue executing the following steps.
In computational terms, we used pseudo-code for the algorithm, since this is a list of actions not specific to any programming language.
Also we can say this is a structured programming example due to the sequential nature of the cooking process.
Answer:
The program in Python is as follows:
num1 = int(input())
num2 = int(input())
if num1 >=0 and num2 >= 0:
print(num1+num2)
elif num1 <0 and num2 < 0:
print(num1*num2)
else:
if num1>=0:
print(num1**2)
else:
print(num2**2)
Explanation:
This gets input for both numbers
num1 = int(input())
num2 = int(input())
If both are positive, the sum is calculated and printed
<em>if num1 >=0 and num2 >= 0:</em>
<em> print(num1+num2)</em>
If both are negative, the products is calculated and printed
<em>elif num1 <0 and num2 < 0:</em>
<em> print(num1*num2)</em>
If only one of them is positive
else:
Calculate and print the square of num1 if positive
<em> if num1>=0:</em>
<em> print(num1**2)</em>
Calculate and print the square of num2 if positive
<em> else:</em>
<em> print(num2**2)</em>
D)It did not change the curriculum because Scopes lost the case.