All categories

3 years ago

What's the area of the composite figure below ?

Mathematics

1 answer:

JulsSmile [24]3 years ago

3 0

Answer:

31.13

Step-by-step explanation:

If you look carefully, you will find a semicircle and a triangle.

The total area is =

$\frac{\pi r^{2}}{2} + \frac{1}{2} \times base \times height\\$

r = 4 - 0 = 4
base = |-4-0 | = 4
height = 14 - 9 = 5

So if we put the values:

$\frac{\pi \times 4^{2}}{2} + \frac{1}{2} \times 4 \times 3\\= 31.13$

You might be interested in

Can someone help me with this question???

Softa [21]

Guys I got my amazon gift gift card for hdusvxdhhsgevd xhx xhs d

4 0

2 years ago

What is the volume of a sphere if it has a radius of 3 centimeters? (Use 3.14 for TT.)

snow_tiger [21]

Answer:

9.52

Step-by-step explanation:

4 0

3 years ago

Match the description with the ratio. 1. There are three silver bows for every four red bows in a bag. 3:10 2. There are four re

timofeeve [1]

1.3:4
2.4:10
3.6:10
4.3:10

5 0

3 years ago

Add all of the times together into min.

tatuchka [14]

Answer:

422mins and 8sec

Step-by-step explanation:

အားလုံးကိုပေါင်းလိုက်

7 0

3 years ago

Use your understanding of the unit circle and trigonometric functions to find the values requested.

vfiekz [6]

Answer:

a) For this case we can use the fact that $sin (\pi/3) = \frac{\sqrt{3}}{2}$

And for this case since we ar einterested on $-\frac{\pi}{3}$ and we know that the if we are below the y axis the sine would be negative then:

$sin (-\pi/3) = -\frac{\sqrt{3}}{2}$

b) From definition we can use the fact that $tan x= \frac{sin x}{cos x}$ and we got this:

$tan (5\pi/4) = \frac{sin(5\pi/4)}{cos(5\pi/4)}$

We can use the notabl angle $\pi/4$ and we know that :

$sin (\pi/4) = cos(\pi/4) = \frac{\sqrt{2}}{2}$

Then we know that $5\pi/4$ correspond to 225 degrees and that correspond to the III quadrant, and we know that the sine and cosine are negative on this quadrant. So then we have this:

$tan (5\pi/4) = \frac{sin(5\pi/4)}{cos(5\pi/4)}= \frac{\frac{sqrt{2}}{2}}{\frac{\sqrt{2}}{2}} = 1$

Step-by-step explanation:

For this case we can use the notable angls given on the picture attached.

Part a

For this case we can use the fact that $sin (\pi/3) = \frac{\sqrt{3}}{2}$

And for this case since we ar einterested on $-\frac{\pi}{3}$ and we know that the if we are below the y axis the sine would be negative then:

$sin (-\pi/3) = -\frac{\sqrt{3}}{2}$

Part b

From definition we can use the fact that $tan x= \frac{sin x}{cos x}$ and we got this:

$tan (5\pi/4) = \frac{sin(5\pi/4)}{cos(5\pi/4)}$

We can use the notabl angle $\pi/4$ and we know that :

$sin (\pi/4) = cos(\pi/4) = \frac{\sqrt{2}}{2}$

Then we know that $5\pi/4$ correspond to 225 degrees and that correspond to the III quadrant, and we know that the sine and cosine are negative on this quadrant. So then we have this:

$tan (5\pi/4) = \frac{sin(5\pi/4)}{cos(5\pi/4)}= \frac{\frac{\sqrt{2}}{2}}{\frac{\sqrt{2}}{2}} = 1$

6 0

3 years ago