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Tasya [4]
3 years ago
13

What's the area of the composite figure below ?

Mathematics
1 answer:
JulsSmile [24]3 years ago
3 0

Answer:

31.13

Step-by-step explanation:

If you look carefully, you will find a semicircle and a triangle.

The total area is =

\frac{\pi r^{2}}{2} + \frac{1}{2} \times base \times height\\

  • r = 4 - 0 = 4
  • base = |-4-0 | = 4
  • height = 14 - 9 = 5

So if we put the values:

\frac{\pi \times 4^{2}}{2} + \frac{1}{2} \times 4 \times 3\\= 31.13

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I-Ready find the measure of angle RST
garik1379 [7]

Answer:

Step-by-step explanation:

You need an image for problem to be solved, please repost it with a image, so it can be solved

3 0
3 years ago
Find x in this 45°-45°-90° triangle.<br> 145972<br> x<br> X=<br> 4.572<br> 9<br> 18
Minchanka [31]
IOS share with you and your family
3 0
3 years ago
Luke is going to repaint both sides of the door of his room. The door is 36 inches long by 80 inches high. His options at the pa
RSB [31]
Alright so since the area of one side of the door is 2,880 inches squared and he wants to paint both sides, you must multiply that by 2.

2880 * 2 = 5760

Since he wants to put 2 coats of paint, this essentially means he wants to paint over everything twice so you must multiply by 2 once more.

5760 * 2 = 11520

This being the total surface area we are going to need to paint. So now we must discover the least amount of money Luke must pay. Knowing we need to cover 11,520 inches worth of door:

4400 * 2 = 8800
8800 + 2200 = 11000
This means we either need to pay another $7 or just buy three gallons.

Best option: Purchase 3 gallons of paint costing 30$


30$

3 0
3 years ago
X+5(x-1)=(x-3)4-1 anyone?
Troyanec [42]
Hi there!

First of all simplify x+5(x-1)=(x-3)4-1.
This would make 6x-5=4x-13.

Next, subtract 4x from both sides.
6x-5-4x=4x-13-4x
2x-5=-13

Then add 5 to both sides.
2x-5+5=-13+5
2x=-8

Finally divide by 2 on both sides.
2x/2=-8/2
x=-4

Your answer is -4.

Hope this helped!
3 0
3 years ago
Using the quadratic formula to solve 4x2 – 3x + 9 = 2x + 1, what are the values of x? StartRoot 1 plus-or-minus StartRoot 159 En
castortr0y [4]

For this case we have that a quadratic equation is of the form:

ax ^ 2 + bx + c = 0

The roots are given by:

x = \frac {-b \pm \sqrt {b ^ 2-4 (a) (c)}} {2 (a)}

We have the following equation:

4x ^ 2-3x + 9 = 2x + 1\\4x ^ 2-3x-2x + 9-1 = 0\\4x ^ 2-5x + 8 = 0

We look for the roots:

x = \frac {- (- 5) \pm \sqrt {(- 5) ^ 2-4 (4) (8)}} {2 (4)}\\x = \frac {5 \pm \sqrt {25-128}} {8}\\x = \frac {5 \pm \sqrt {-103}} {8}

We have to:

i ^ 2 = -1

So:

x = \frac {5 \pm \sqrt {103i ^ 2}} {8}\\x = \frac {5 \pm i \sqrt {103}} {8}

We have two imaginary roots:

x_ {1} = \frac {5 \ + i \sqrt {103}} {8}\\x_ {2} = \frac {5 \ -i \sqrt {103}} {8}

Answer:

x_ {1} = \frac {5 \ + i \sqrt {103}} {8}\\x_ {2} = \frac {5 \ -i \sqrt {103}} {8}

8 0
4 years ago
Read 2 more answers
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