We have the following expression:
y = logbx
We clear x of the expression.
We have then:
b ^ y = b ^ (logbx)
Rewriting:
x = b ^ y
Substituting we have:
x = b ^ 0
x = 1
Answer:
If (x, 0) lies on the graph of y = logbx, then:
x = 1
Answer:
596.34m approx
Step-by-step explanation:
Given data
Let the Starting point be x
A helicopter flew north 325 meters from x
Then flew east 500 meters
Let us apply the Pythagoras theorem to solve for the resultant which is the distance from the starting position
x^2= 325^2+500^2
x^2=105625+250000
x^2= 355625
x= √355625
x=596.34m
Hence the distance from the starting point is 596.34m approx
So you have to simplify
(9 x 10 x 18) 2 + (5 x 10 x 18) (-7) + (5 x 9 x 18)
(-11) + (5 x 9 x 10)
5 x 9 x 10 x 18
1620 x 2 + 900 (-7) + 810(-11) + 450 x 5
x 5 x 9 x 10 x 18
The answer would be -6/5
Answer:
-2
Step-by-step explanation:
5+14a=9a-5
+5 +5
10+14a=9a
-9a -9a
10+5a=0
-5a -5a
10= -5a
÷5 ÷5
2= -a
*-1 *-1
-2=a
