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Alexxandr [17]
3 years ago
7

Recently in the United States, there were about 300,000,000 cell phone users. That same year, there were 5.7 x 10 to the 9th pow

er, cell phone users worldwide. About how many times larger was the number of cell phone users worldwide then in the United States
Mathematics
1 answer:
Arisa [49]3 years ago
3 0
5.7*10^9-300,000,000= 5,400,000,000
5,400,000,000=5.4*10^9
So the cell phone users worldwide is 5.4*10^9 more than the cell phone users in USA.
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Step-by-step explanation:

\begin{gathered}\frak \red{Given}\:\begin{cases} \:\quad\sf  Acceleration \:of \ \: a\:body\:,\:a\:=\:\pmb{\frak{5\:m/s^2\:}}\:\\ \:\quad\sf Force \:Exerted\:on\:a\:body\:,\:F\:=\:\pmb{\frak{\:4\times 10^5\: dynes\:}}\:\end{cases}\\\\\end{gathered}

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We're Provided with the , Acceleration (a) , and Force Exerted (F) on a body and , we'll find Mass (m) of the object using the <u>relation</u>

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\underline {\pmb{\sf \: F\:=\:m\:\times \:a \:}}

\\ \twoheadrightarrow \sf F \:=\:m\:\times \:a

: \rightarrow \sf 4 \:\times 10^5 \:=\:m\:\times \:5\:

\\  \\  \\ \\\twoheadrightarrow \sf 4 \:=\:m\:\times \:5\:\:\Bigg\lgroup \:1 \:N\:=\:1\:\times 10^5\:dynes\:\Bigg\rgroup\\

\\ \twoheadrightarrow \sf 4 \: \:=\:m\:\times \:5\:\\\\\\

\twoheadrightarrow \sf 5m\:=\:4\:\\

\twoheadrightarrow \sf m \cancel{\dfrac{4}{5}}\\\\

\ \twoheadrightarrow \pmb {\underline {\boxed {\purple {\:\frak{ \:m\:\:=\:0.8\:kg\:}}}}}\:\bigstar \: \\

\begin{gathered}\therefore \:\underline {\sf \: Hence,\:Mass\:of\:a\:body\:is\:\pmb{\sf 0.8\:kg\:}\:.}\:\\\\\end{gathered}

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