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vladimir1956 [14]
3 years ago
12

Jeb has to pay a plumber $65 to come to his house and $40 per hour after that .write an equation for the cost (y) based on the n

umber of hours(x)
Mathematics
2 answers:
aleksley [76]3 years ago
6 0
Y=40x+65 hope this helps !
zlopas [31]3 years ago
5 0
65+40x=y
Hope this helps
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H(x) = 1/3x - 1 if h (15)
dalvyx [7]

Answer:

(

h

∘

f

∘

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is known as a composite function. Here's how composite functions work:

let's say that  

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=

1

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(

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now produces a  

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g

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3

⇒

h

(

17

3

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Therefore,

(

h

∘

f

∘

g

)

(

1

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=

17

Based on this, to find the function for  

(

h

∘

f

∘

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(

x

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(combined from right to left, by the way), simply replace  

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(

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with the function  

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in  

h

(

x

)

with the function of  

(

f

∘

g

)

(

x

)

, to get  

(

h

∘

f

∘

g

)

(

x

)

.

This, simplified, is equal to  

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5 0
3 years ago
Kyle leaves a 15% tip for lunch bill of $12 what amount tip does Kyle leave
Aleonysh [2.5K]
Kyle leaves 1.80 because you have to do 0.15*12
8 0
3 years ago
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Simplify the expression (7-(-1))2+(-2)
erastova [34]
The simplified version of this equation is 8
8 0
3 years ago
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How much of 30% HCI and 45% HCI would be needed to mix and produce 50 liters of 35% HCI
VladimirAG [237]

Answer:

  • 33 1/3 liters of 30%
  • 16 2/3 liters of 45%

Step-by-step explanation:

Let x represent the liters of 45% solution needed. Then the amount of HCl in the mix is ...

  0.45x +0.30(50 -x) = 0.35(50)

  0.15x = 0.05(50) . . . . . simplify, subtract 0.30(50)

  x = (0.05/0.15)(50) = 50/3 = 16 2/3 . . . liters of 45% HCl

33  1/3 liters of 30% and 16 2/3 liters of 45% HCl are needed.

_____

<em>Comment on the solution</em>

You may notice that the general solution to a mixture problem of this sort is that the fraction of the mix that is the highest contributor is ...

  (mix % - low %) / (high % - low %) = (.35 -.30) / (.45 -.30) = .05/.15 = 1/3

5 0
3 years ago
Please show me the procedure o 4+(-2)
Stella [2.4K]
Since the signs are different, you have to subtract. 2
7 0
4 years ago
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