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Neporo4naja [7]
3 years ago
10

What are the factor of pair of number?

Mathematics
1 answer:
Sedbober [7]3 years ago
8 0
C…………………………x Mmmmmvvtvjvj I j I
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On the first day of school, the cafeteria serves hot dogs and hamburgers together. The cafeteria serves hot dogs every 6th schoo
kumpel [21]

Answer:

The Answer is 12 days or times.

Step-by-step explanation:

The LCM of 6 is 3 and 2, the LCM of 4 is 2 and 1, so we multiply 3 by 2 and 4 by 2 together to get 12, which is the number of days or times.

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joe drove 408 miles using 16 gallons of gas at this ratr how many mokrs would he drive using 11 gallons of gas
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I was on the right track, lol. 280.5 miles.
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Dex estimates that 49,892 ÷ 0.89 is about 5,000. Is his estimate reasonable? Why or why not?
SVEN [57.7K]

Answer:yes

Step-by-step explanation:

because 0.89 is a very small number so itd be reasonable for it to be a large number

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3 years ago
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The ratio of income of a person to his savings is 10:1 if his saving for one year is 6000 what is his monthly income
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his monthly income is 60000

5 0
3 years ago
In a certain town, the amount of sulfur oxide in the air, S, in tons, is related to the town’s population, P, in people. The rel
Lady bird [3.3K]

Answer:

Change in sulfur oxide in the air = \frac{\textup{110010}}{\textup{S}}

Step-by-step explanation:

Data provided in the question:

Relation between the amount of sulfur oxide in the air and the population as:

S² = 110P² + 20P + 600

Population growth rate, \frac{\textup{dP}}{\textup{dt}}  = 10 people per month

Now,

change in sulfur oxide with time i.e \frac{\textup{dS}}{\textup{dt}}

differentiating the given relation with respect to time 't'

we have

2S\frac{\textup{dS}}{\textup{dt}} =  2\times110P\frac{\textup{dP}}{\textup{dt}}  + 20

at P = 100 and  \frac{\textup{dP}}{\textup{dt}}  = 10 people per month

we have

2S\frac{\textup{dS}}{\textup{dt}} = 2 × 110 × 100 × 10 + 20

or

2S\frac{\textup{dS}}{\textup{dt}} = 220020

or

\frac{\textup{dS}}{\textup{dt}} = \frac{\textup{220020}}{\textup{2S}}

or

Change in sulfur oxide in the air = \frac{\textup{110010}}{\textup{S}}

8 0
3 years ago
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