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2 years ago

I'm sry pls help! im bad at math:(((

Mathematics

1 answer:

Basile [38]2 years ago

5 0

Choice B: I’m good a math and

STEP BY Step EXPLAINATION: 45 is double 25 and if you double 3.49=6.98 and choise B shows 4.79 soooo it’s choise B boooom.

Pls mark me Brainlyist

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HELP DUE IM THIRTY MINUTES

Alexandra [31]

Answer:

I do not know this answer to the question. I am so sorry. Ask "LucasPeed"

Step-by-step explanation:

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2 years ago

Read 2 more answers

Factor the following :

Otrada [13]

Answer:

(x - 3)(x² + 4)

Step-by-step explanation:

x³ - 3x² + 4x - 12 ( factor first/second and third/fourth terms )

= x²(x - 3) + 4(x - 3) ← factor out (x - 3 from each term

= (x - 3)(x² + 4)

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2 years ago

The prior probabilities for events A1 and A2 are P(A1) = 0.20 and P(A2) = 0.80. It is also known that P(A1 ∩ A2) = 0. Suppose P(

Umnica [9.8K]

Answer:

(a) $A_1$ and $A_2$ are indeed mutually-exclusive.

(b) $\displaystyle P(A_1\; \cap \; B) = \frac{1}{20}$ , whereas $\displaystyle P(A_2\; \cap \; B) = \frac{1}{25}$ .

(d) $\displaystyle P(A_1 \; |\; B) \approx \frac{5}{9}$ , whereas $P(A_1 \; |\; B) = \displaystyle \frac{4}{9}$

Step-by-step explanation:

$P(A_1 \; \cap \; A_2) = 0$ means that it is impossible for events $A_1$ and $A_2$ to happen at the same time. Therefore, event $A_1$ and $A_2$ are mutually-exclusive.

By the definition of conditional probability:

$\displaystyle P(B \; | \; A_1) = \frac{P(B \; \cap \; A_1)}{P(B)} = \frac{P(A_1 \; \cap \; B)}{P(B)}$ .

Rearrange to obtain:

$\displaystyle P(A_1 \; \cap \; B) = P(B \; |\; A_1) \cdot P(A_1) = 0.25 \times 0.20 = \frac{1}{20}$ .

Similarly:

$\displaystyle P(A_2 \; \cap \; B) = P(B \; |\; A_2) \cdot P(A_2) = 0.80 \times 0.05 = \frac{1}{25}$ .

Note that:

$\begin{aligned}P(A_1 \; \cup \; A_2) &= P(A_1) + P(A_2) - P(A_1 \; \cap \; A_2) = 0.20 + 0.80 = 1\end{aligned}$ .

In other words, $A_1$ and $A_2$ are collectively-exhaustive. Since $A_1$ and $A_2$ are collectively-exhaustive and mutually-exclusive at the same time:

$\displaystyle P(B) = P(B \; \cap \; A_1) + P(B \; \cap \; A_2) = \frac{1}{20} + \frac{1}{25} = \frac{9}{100}$ .

By Bayes' Theorem:

$\begin{aligned} P(A_1 \; |\; B) &= \frac{P(B \; | \; A_1) \cdot P(A_1)}{P(B)} \\ &= \frac{0.25 \times 0.20}{9/100} = \frac{0.05 \times 100}{9} = \frac{5}{9}\end{aligned}$ .

Similarly:

$\begin{aligned} P(A_2 \; |\; B) &= \frac{P(B \; | \; A_2) \cdot P(A_2)}{P(B)} \\ &= \frac{0.05 \times 0.80}{9/100} = \frac{0.04 \times 100}{9} = \frac{4}{9}\end{aligned}$ .

6 0

2 years ago

4x+11<23 solve for x

jarptica [38.1K]

Let's solve your inequality step-by-step.
<span><span><span>4x</span>+11</span><23
</span>Step 1: Subtract 11 from both sides.
<span><span><span><span>4x</span>+11</span>−11</span><<span>23−11</span></span><span><span>4x</span><12
</span>Step 2: Divide both sides by 4.<span><span><span>4x</span>4</span><<span>124</span></span><span>x<3
</span><u>Answer:
</u><span> x<<span>3</span></span>

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3 years ago

!! WILL MARK BRAINLIEST PLZ HELP !!

Luba_88 [7]

Answer:

Step-by-step explanation:

.................................

5 0

2 years ago

I'm sry pls help! im bad at math:(((​

I'm sry pls help! im bad at math:(((