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9966 [12]
3 years ago
11

24 ounce package of strawberries for $3.32. What was the price per pound for the strawberries

Mathematics
1 answer:
valentina_108 [34]3 years ago
6 0
3.32 / 24 = 0.138 per oz

1 lb = 16 oz

16 * 0.138 = 2.208...rounds to 2.21 per lb <==
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The segment from (-1,4) to (2,-2) extended three times then terminal point of segment is
ziro4ka [17]
There are various ways in which you could do this problem.  I'm going to share what I think is one of the faster ways.

Instead of thinking of jumping from (-1,4) TO (2,-2),  Consider the horiz. jump separately and the vertical jump separately.  From -1 to 2 is 3 units.  Three times that is 9 units.  Add 9 to -1, obtaining 8.  That's the horiz. component of the terminal point.

From 4 to -2 is -6 units.  Mult. that by 3.  The result is the vert. comp of the terminal point. 
5 0
3 years ago
Ok need help this is the question :Use the Pythagorean theorem to write an equation for the distance Jane's trainer bikes.
IRINA_888 [86]

Answer:

<em>Jane traveled 8 miles farther then her trainer</em>

Step-by-step explanation:

<u>The Pythagora's Theorem</u>

In any right triangle, the square of the measure of the hypotenuse is the sum of the squares of the legs. This can be expressed with the formula:

c^2=a^2+b^2

Where

c = Hypotenuse or largest side

a,b = Legs or shorter sides

Jane's path from the Health Club to the end of her route describes two sides of a right triangle of lengths a=16 miles and b=12 miles.

Her total distance traveled is 16 + 12 = 28 miles

Her trainer goes directly from the Health Club to meet her through the hypotenuse of the triangle formed in the path.

We can calculate the length of his route as:

c=\sqrt{16^2+12^2}

c=\sqrt{256+144}=\sqrt{400}=20

c = 20 miles

The difference between their traveled lengths is 28 - 20 = 8 miles

Jane traveled 8 miles farther then her trainer

8 0
2 years ago
3456.8 round the number below to the nearest whole number one place
fiasKO [112]

Answer:

I do not understand this question

4 0
2 years ago
Write an informal proof to show triangles ABC and DEF are similar. Please don’t answer if you don’t know!!
Mila [183]

Answer:

ΔABC ~ ΔDEF

Step-by-step explanation:

If the given triangles ΔABC and ΔDEF are similar,

Their corresponding sides will be proportional.

\frac{\text{AB}}{\text{DE}}=\frac{\text{BC}}{\text{EF}}=\frac{\text{AC}}{\text{DF}}

By substituting the measures of the given sides,

\frac{4}{2}=\frac{6}{3}=\frac{2}{1}

2 = 2 = 2

Since, corresponding sides of both the triangles are proportional, both the triangles will be similar.

ΔABC ~ ΔDEF

8 0
3 years ago
Point XXX is located at (3, 2)(3,2)left parenthesis, 3, comma, 2, right parenthesis. Point YYY is located at (3, -8)(3,−8)left p
NeX [460]

Answer:

10

Step-by-step explanation:

Given that:

Point X = (3, 2)

Point Y = (3, - 8)

Distance of point X to Y:

Distance = √(x2 - x1)^2 + (y2 - y1)^2

X1 = 3 ; y1 = 2 ; x2 = 3 ; y2 = - 8

Distance = √(3 - 3)^2 + (-8 - 2)

Distance = √(0)^2 + (-10)^2

Distance = √0 + 100

Distance = √100

Distance = 10

7 0
2 years ago
Read 2 more answers
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