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9966 [12]
3 years ago
11

24 ounce package of strawberries for $3.32. What was the price per pound for the strawberries

Mathematics
1 answer:
valentina_108 [34]3 years ago
6 0
3.32 / 24 = 0.138 per oz

1 lb = 16 oz

16 * 0.138 = 2.208...rounds to 2.21 per lb <==
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Please help me with this trigonometry question:
zzz [600]

Answer:

The distance from A to B is 736.2 to the nearest tenth foot

Step-by-step explanation:

In ΔCAB

∵ m∠CAD = 30° ⇒ exterior angle of Δ at vertex A

∴ m∠CAD = m∠ACB + m∠ABC

∵ m∠ABC = 20°

∴ m∠ACB = 30° - 20° = 10°

We will use the sin rule to find the distance AB

∵ \frac{sin20}{1450}=\frac{sin10}{AB}

∴ AB=\frac{1450(sin10)}{sin20}=736.1842936 ≅ 736.2 to the nearest tenth foot

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How much is each taco shell if you do 5.36 divided by 20
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It would be 26 cents per shell
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A programmer plans to develop a new software system. In planning for the operating system that he will​ use, he needs to estimat
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Answer:

a) n = 9604

b) n = 381

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

z is the zscore that has a pvalue of 1 - \frac{\alpha}{2}.

The margin of error is:

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

90% confidence level

So \alpha = 0.1, z is the value of Z that has a pvalue of 1 - \frac{0.1}{2} = 0.95, so Z = 1.645.

a. Assume that nothing is known about the percentage of computers with new operating systems. n = ?

When we do not know the proportion, we use \pi = 0.5, which is when we are going to need the largest sample size.

The sample size is n when M = 0.01.

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

0.01 = 1.96\sqrt{\frac{0.5*0.5}{n}}

0.01\sqrt{n} = 1.96*0.5

\sqrt{n} = \frac{1.96*0.5}{0.01}

(\sqrt{n})^{2} = (\frac{1.96*0.5}{0.01})^{2}

n = 9604

b. Assume that a recent survey suggests that 99% of computers use a new operating system. n = ?

Now we have that \pi = 0.99. So

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

0.01 = 1.96\sqrt{\frac{0.99*0.01}{n}}

0.01\sqrt{n} = 1.96*\sqrt{0.99*0.01}

\sqrt{n} = \frac{1.96*\sqrt{0.99*0.01}}{0.01}

(\sqrt{n})^{2} = (\frac{1.96*\sqrt{0.99*0.01}}{0.01})^{2}

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Rouding up

n = 381

7 0
3 years ago
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Flauer [41]

Answer:

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Firlakuza [10]
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