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morpeh [17]
3 years ago
8

What is the answer??

Mathematics
1 answer:
eduard3 years ago
6 0
If the bikes original price was $112.99...
and it's 75% off you have to multiply the original price by the percentage thats left which is 25%...
$112.99×.25%=28.25
ANSWER: b)28.25
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Only some of the students in the levell swim lessons move up to Level 2 at the end of the
Aleksandr-060686 [28]

Answer:

17/24, 7/12, 3/4, 2/3

Step-by-step explanation:

5 0
3 years ago
Find the indicated term of the given arithmetic sequence. a1 = 115, d = 8, n = 14
olya-2409 [2.1K]
I took the same test and I put the answer D. 1487 and I got it wrong. The correct answer was 
A.3
3 0
3 years ago
(X^2+x-6)(2x^2+4x) factor completely
MissTica

Answer:

2x\left(x-2\right)\left(x+3\right)\left(x+2\right)

Step-by-step explanation:

Lets go ahead and take a step by step approach to solving your problem.

First we must start by factoring x^2+x-6.

To do this, we must break the expression into groups! Although I will also provide a definition to help you understand! For ax^2+bx+c we need to find u, v > u\cdot \:v=a\cdot \:c and u+v=b which we will group into \left(ax^2+ux\right)+\left(vx+c\right).

The values we have are...a=1,\:b=1,\:c=-6 and u\cdot v=-6,\:u+v=1.

Now we need the factors of 6 which are 1, 2, 3 and 6. We also need the negative factors which you get simply by multiplying the positives by -1 or just reversing them.

Now we need to check for every two factors if u + v = 1.

\mathrm{Check}\:u=1,\:v=-6: \:u\cdot v=-6,\:u+v=-5 \Rightarrow  \mathrm{False}

\mathrm{Check}\:u=2,\:v=-3: \:u\cdot v=-6,\:u+v=-1 \Rightarrow  \mathrm{False}

\mathrm{Check}\:u=3,\:v=-2: \:u\cdot v=-6,\:u+v=1 \Rightarrow  \mathrm{True}

\mathrm{Check}\:u=6,\:v=-1: \:u\cdot v=-6,\:u+v=5 \Rightarrow  \mathrm{False}

Therefore u=3,\:v=-2.

Now we want to \mathrm{Group\:into\:}\left(ax^2+ux\right)+\left(vx+c\right). Which is \left(x^2-2x\right)+\left(3x-6\right).

Now we must factor x from x^2-2x.

Lets apply the exponent rule of a^{b+c}=a^ba^c which means x^2=xx.

Therefore we now have xx - 2x. Lets factor out the common term of x to get x(x - 2).

Now factor 3 out of 3x-6.

Rewrite 6 as 3 * 2. 3x-3\cdot \:2.

Now factor out the common term of 3 > 3\left(x-2\right).

x\left(x-2\right)+3\left(x-2\right) > Factor out the common term of x - 2 > \left(x-2\right)\left(x+3\right).

Now lets factor 2x^2+4x.

Apply the previous exponent rule of a^{b+c}=a^ba^c > x^2=xx > 2xx+4x.

Now rewrite 4 as 2 * 2 > 2xx+2\cdot \:2x.

Now factor out the common term of 2x to get 2x(x + 2).

Combine it all and we get 2x\left(x-2\right)\left(x+3\right)\left(x+2\right).

Hope this helps!

7 0
3 years ago
Is algebra.
bonufazy [111]
I believe the GCF would be 2n
8 0
3 years ago
(8,8) and (6,-4) slope
dem82 [27]

Answer:

the formula to find slope is m=y1-y2/x1-x2

using this formula 8-6/8-(-4)

=2/8+4

=2/12 simplify

=1/6

5 0
3 years ago
Read 2 more answers
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