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blondinia [14]
3 years ago
12

Solve the equation. (enter your answers as a comma-separated list. round your answers to four decimal places.) x2e5x + 3xe5x − e

5x = 0 x =
Mathematics
1 answer:
aleksley [76]3 years ago
7 0
It's essential that you use " ^ " to indicate exponentiation if you want to communicate your ideas here accurately.

<span>x2e5x + 3xe5x − e5x = 0 should be written as

x^2e^(5x) + 3xe^(5x) - 1e^(5x) = 0.

e^(5x) can be factored out of all four terms, leaving us with


e^(5x) [x^2 + 3x - 1] = 0.  e^(5x) is never zero, so no solution there.

However, we can set x^2 + 3x - 1 equal to zero and solve for x:

         -3 plus or minus sqrt(3^2 - 4(1)(-1) )
x = ----------------------------------------------------
                                 2
        -3 plus or minus sqrt(13)
   = ----------------------------------------
                                2

So the original equation has two roots.</span>
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storchak [24]

Answer:

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Step-by-step explanation:

use variables for the vans and buses

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<em><u>remember</u></em><em><u> </u></em><em><u>to</u></em><em><u> </u></em><em><u>number</u></em><em><u> </u></em><em><u>your</u></em><em><u> </u></em><em><u>equations</u></em>

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make x the subject of one equation

and label it equation 3

6x=412—7y

x =  \frac{206}{3}  -  \frac{7y}{6} .............3

subs 3 into 2

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subs 4 into 1

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