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3 years ago

Simplify using the distributive property

Mathematics

1 answer:

ad-work [718]3 years ago

8 0

Answer:

3/5 is the number that can be distributed across two terms inside parentheses.

you might not need it but:

x = 5

Step-by-step explanation:

<u>3/5(x - 10)</u> = 18 - 4x - 1

using distributive property, open the parentheses:

<u>3/5x - 6 </u>= 18 - 4x - 1

Simplify:

3/5x + 4x = 17 + 6

4⅗x = 23

x = 5

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yes

Step-by-step explanation:

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3 years ago

Read 2 more answers

Is 4y - 8 > 10 true?

steposvetlana [31]

4y-8>10

Add 8

4y-8+8>10+8

4y>18

Now divide both sides by 4

4y/4 > 18/4

y>9/2

Now let's see if it will be true

Replace y by its value

4(9/2)-8>10

36/2 -8 > 10

18-8 > 10

10 > 10

That's false because 10 can not smaller than 10

so it should be = instead

Answer : False

I hope that's help:)

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3 years ago

Quadrilateral ABCD is inscribed in a circle. Find the measure of each of the angles of the quadrilateral. Show your work.

LuckyWell [14K]

Step-by-step explanation:

Quadrilateral ABCD is inscribed in a circle.

Opposite angles of a Quadrilateral are Supplementary.

$\therefore \: \angle A + \angle C = 180° \\ \therefore \:(2x + 3) \degree+ (2x + 1) \degree = 180° \\ \therefore \: (4x + 4) \degree = 180° \\ \therefore \: (4x + 4) = 180 \\ \therefore \: 4x = 180 - 4 \\ \therefore \: 4x = 176 \\ \therefore \: x = \frac{176}{4} \\ \therefore \: x = 44 \\ \\ m\angle A = (2x + 3) \degree \\ = (2 \times 44 + 3) \degree \\ = (88 + 3) \degree \\ \huge \red{ \boxed{ \therefore \: m\angle A =91 \degree}} \\ \\ m\angle C = (2x + 1) \degree \\ = (2 \times 44 + 1) \degree \\ = (88 + 1) \degree \\ \huge \red{ \boxed{ \therefore \: m\angle C=89\degree}} \\ \\ m\angle D= (x - 10) \degree \\ = (44 - 10) \degree \\ \huge \red{ \boxed{ \therefore \: m\angle D =34\degree}} \\ \\ similarly \\ \\ \huge \red{ \boxed{ \therefore \: m\angle B = 146\degree}} \\ \\$

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3 years ago

Although cities encourage carpooling to reduce traffic congestion, most vehicles carry only one person. For example, 64% of vehi

ira [324]

Answer:

a) 0.7291 is the probability that more than half out of 10 vehicles carry just 1 person.

b) 0.996 is the probability that more than half of the vehicles carry just one person.

Step-by-step explanation:

We are given the following information:

A) Binomial distribution

We treat vehicle on road with one passenger as a success.

P(success) = 64% = 0.64

Then the number of vehicles follows a binomial distribution, where

$P(X=x) = \binom{n}{x}.p^x.(1-p)^{n-x}$

where n is the total number of observations, x is the number of success, p is the probability of success.

Now, we are given n = 10

We have to evaluate:

$P(x \geq 6) = P(x =6) +...+ P(x = 10) \\= \binom{10}{6}(0.64)^6(1-0.64)^4 +...+ \binom{10}{10}(0.64)^{10}(1-0.79)^0\\=0.7291$

0.7291 is the probability that more than half out of 10 vehicles carry just 1 person.

B) By normal approximation

Sample size, n = 92

p = 0.64

$\mu = np = 92(0.64) = 58.88$

$\sigma = \sqrt{np(1-p)} = \sqrt{92(0.64)(1-0.64)} = 4.60$

We have to evaluate the probability that more than 47 cars carry just one person.

$P(x \geq 47)$

After continuity correction, we will evaluate

$P( x \geq 46.5) = P( z > \displaystyle\frac{46.5 - 58.88}{4.60}) = P(z > -2.6913)$

$= 1 - P(z \leq -2.6913)$

Calculation the value from standard normal z table, we have,

$P(x > 46.5) = 1 - 0.004 = 0.996 = 99.6\%$

0.996 is the probability that more than half out of 92 vehicles carry just one person.

5 0

3 years ago