No, not at all.
The general quadratic equation is
Ax² + Bx + C = 0 .
The roots are real only if (B² - 4AC) is not negative.
That means if you graph it, it touches or crosses the x-axis.
If the graph is up in the air and never touches the x-axis,
then it has no real roots.
Answer:
y=68.38172757
Step-by-step explanation:
Take the inverse cosine of both sides of the equation to extract
y from inside the cosine.
y=arccos(7/19)
y=68.38172757
The cosine function is positive in the first and fourth quadrants. To find the second solution, subtract the reference angle from
360 to find the solution in the fourth quadrant. y=360−68.38172757
y=68.38172757+360n,291.61827242+360n, for any integer n
4A = E , A=E/4-----(1)
B/4=E , B=4E-------(2)
C+4=E, C=E-4------(3)
D-4=E, D=E+4------(4)
Substitute all values in 5th equation,
A+B+C+D=100 = E/4 + 4E + E-4+ E+4 =100
E/4 + 6E = 100
25E = 400
E=16 ANS....