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jeka57 [31]
2 years ago
6

Find the value of x that will make AB А 9x - 40 В. 3x + 20 x = [?]

Mathematics
1 answer:
Charra [1.4K]2 years ago
7 0

Answer:

x = 10

Step-by-step explanation:

∵ Both angle ∠A and are corresponding angles.

∠A = ∠B

9x - 40 = 3x + 20

9x = 3x + 20 + 40

9x - 3x = 20 + 40

6x = 60

x = 60/6

x = 10

∴ x = [10]

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lakkis [162]
4/5=0.8
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5 0
3 years ago
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Review the steps of the proof of the identity
astraxan [27]

Answer:

step 2

and then step 3 : the error neutralized the error of step 2

Step-by-step explanation:

sin(a + b) = sin(a)cos(b) + cos(a)sin(b)

and because

sin(-b) = -sin(b)

cos(-b) = cos(b)

we have

sin(a - b) = sin(a)cos(-b) + cos(a)sin(-b) =

= sin(a)cos(b) - cos(a)sin(b)

3pi/2 = 270° or -90°.

sin(3pi/2) = sin(270) = sin(-90) = -1

that means, it is the full radius straight down from the center of the circle.

cos(3pi/2) = cos(270) = cos(-90) = cos(90) = 0

so, step 1 is correct :

sin(A - 3pi/2) = sin(A)cos(3pi/2) - cos(A)sin(3pi/2) =

= sin(A)×0 - cos(A)×(-1) (correct step 2)

but as we see, the provided step 2 is incorrect.

it should have been the indicated

sin(A)×0 - cos(A)×(-1)

and NOT the provided

sin(A)×0 + cos(A)×(-1)

step 3 based on the erroneous step 2 should then have been

sin(A)×0 - (1)cos(A)

but instead another error with the sign was made that neutralized the error of step 2 and we got after this second mistake by pure chance the overall correct step 3

sin(A)×0 + (1)cos(A)

so, again, the first error was made in step 2.

but technically, there was also a consecutive error made in step 3 to bring everything back to the correct approach.

4 0
2 years ago
Someone help with this
elena-14-01-66 [18.8K]

The quadrants are I, II, III, and IV, (meaning 1, 2, 3, and 4). The first quadrant is in the upper right, which has both positive x and positive y values. The second quadrant is the upper left, which has negative x and positive y values. The third quadrant is the lower left, which has both negative x and y values. The fourth quadrant is the lower right, which has positive x and negative y values. Using this knowledge and our positive and negative signs, the following are the answers to questions 1-6.

1) (-4, -2) - Quadrant III, both x and y are negative

2) (0, -7) - This point is actually on the y-axis. The x value is 0 and the y value is -7, so the graph is 7 units down from the origin on the y-axis.

3) (0,0) - This point is the origin, or where the x and y axes cross (the middle of the graph).

4) (6, -9) - This point is in Quadrant IV, because it has a positive x value and a negative y value

5) (3,5) - This point is in Quadrant I, because both the x and y values are positive.

6) (8,0) - This point is on the x-axis. The y-value is zero, so this point is 8 units to the right of the origin between Quadrant I and Quadrant IV.

Using the knowledge presented above, to graph the points given to you in the second part of the problem, first you can figure out what quadrant or part of the graph the point is on. Then, you can count the number of units (squares on the graph) in the right direction (remember that up is positive on the y-axis and down is negative, and to the right is positive on the x-axis and to the left is negative) in order to plot the points. Then, you must connect the points that correspond to the same figure in order to create the figures.

Please comment if you have any questions!

Hope this helps!

7 0
3 years ago
2x^2 + 3x^3 what degree polynomial is this, and how do you know?
german
The degree is 3 ( because the largest exponent on the variable)
7 0
3 years ago
Solve 270=3e^2.4K to the nearest hundredth
mojhsa [17]

Given:

The equation is:

270=3e^{2.4K}

To find:

The solution for the given equation to the nearest hundredth.

Solution:

We have,

270=3e^{2.4K}

Divide both sides by 3.

\dfrac{270}{3}=e^{2.4K}

90=e^{2.4K}

Taking ln on both sides, we get

\ln (90)=\ln e^{2.4K}

\ln (90)=2.4K                  [\because \ln e^x=x]

Divide both sides by 2.4.

\dfrac{\ln (90)}{2.4}=K

\dfrac{4.4998}{2.4}=K           [\because \ln (90)\approx 4.4998]

1.874916667=K

Round the value to the nearest hundredth (two decimal place)

K\approx 1.87

Therefore, the value of K is 1.87.

8 0
3 years ago
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