<span>8(-y+5)+6(2y-7)
= -8y + 40 + 12y - 42 ....expand by using distributive property
= 4y - 2 ...............combine like terms
hope it helps</span>
Answer:
64√2 or 64 StartRoot 2 EndRoot
Step-by-step explanation:
A 45-45-90 traingle is a special traingle. Let's say one of the leg of the triangle is x. The other one is also x because of the isosocles triangle theorem. Therefore, using the pytagorean theorem, you find that x^2+x^2=c^2. 2(x)^2=c^2. You then square root both sides and get c= x√2.
Therefore, the two legs are x and the hypotenuse is x√2. x√2=128 because the question says that the hypotenuse is 128. Solve for x by dividing both sides by √2. X=128/√2. You rationalize it by multiplying the numberator and denominator of the fraction by √2. √2*√2= 2.
X=(128√2)/2= 64√2 cm.
Since X is the leg, the answer would be 64√2
Answer:
r = 6
Step-by-step explanation:
Hello!
-8 - 2(7r + 1) = -94
Add 8 to both sides
-2(7r + 1) = -86
Divide both sides by -2
7r + 1 = 43
Subtract 1 from both sides
7r = 42
Divide both sides by 7
r = 6
Hope this Helps
Answer:
(2)
Step-by-step explanation:
slope:-1/2
y-intercept:1 (because the function passes (0,1))
Answer:
and
are the locations higher than
foot
Step-by-step explanation:
We are given that Meg found one treasure at
foot
We are supposed to find Which of these location are higher than
foot?
i) 
So, this location is not higher than
foot
ii)
So, 
So, this location is higher than
foot
iii) - 1 foot

So,this location is not higher than
foot
iv)-2 feet
So,this location is not higher than
foot
v)
So, this location is higher than
foot