If , then by rationalizing the denominator we can rewrite
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and
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1 answer:
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Speed is given by the distance traveled divided by the time spent.
The net speed with which the plane traveled against the wind is given by
while the speed with which the plane travelled in the return trip is given by 
Let the speed of the plane be v and the speed of the wind be w, then when the plane was traveling against the sun, we have, v - w = 168.57 and when the plane is travelling in the direction of the wind, we have, v + w = 236.
Subtracting the first equation from the second equation, we have: 2w = 236 - 168.57 = 67.43
Thus, w = 67.43 / 2 = 33.715
Therefore, the speed of the wind is approximately 33.7 mi/hr.
The net speed with which the plane traveled against the wind is given by
Let the speed of the plane be v and the speed of the wind be w, then when the plane was traveling against the sun, we have, v - w = 168.57 and when the plane is travelling in the direction of the wind, we have, v + w = 236.
Subtracting the first equation from the second equation, we have: 2w = 236 - 168.57 = 67.43
Thus, w = 67.43 / 2 = 33.715
Therefore, the speed of the wind is approximately 33.7 mi/hr.
Answer:
θ - θ
Step-by-step explanation:
According to the theory of Malus, when a completely plane polarized light is incident on an analyzer, the intensity 'I' of the light wave transmitted by the analyzer is proportional to the square of the cosine of angle between the transmission axes of the polarizer and analyzer. Therefore:
Using the theory of Malus, we need to estimate the angle between the transmission axis θ and the polarization axis θ
.
Thus:
angle θ = θ - θ