1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
butalik [34]
3 years ago
14

(05.01)

Mathematics
2 answers:
GarryVolchara [31]3 years ago
3 0
3x - 6y = 72...reduce by dividing everything by 3
x - 2y = 24...notice how this is exactly the same as the other equation....means that the lines are the same line...meaning infinite solutions
zalisa [80]3 years ago
3 0

Answer:

infinite solutions

Step-by-step explanation:

You might be interested in
A. Do some research and find a city that has experienced population growth.
horrorfan [7]
A. The city we will use is Orlando, Florida, and we are going to examine its population growth from 2000 to 2010. According to the census the population of Orlando was 192,157 in 2000 and 238,300 in 2010. To examine this population growth period, we will use the standard population growth equation N_{t} =N _{0}e^{rt}
where:
N(t) is the population after t years
N_{0} is the initial population 
t is the time in years 
r is the growth rate in decimal form 
e is the Euler's constant 
We now for our investigation that N(t)=238300, N_{0} =192157, and t=10; lets replace those values in our equation to find r:
238300=192157e^{10r}
e^{10r} = \frac{238300}{192157}
ln(e^{10r} )=ln( \frac{238300}{192157} )
r= \frac{ln( \frac{238300}{192157}) }{10}
r=0.022
Now lets multiply r by 100% to obtain our growth rate as a percentage:
(0.022)(100)=2.2%
We just show that Orlando's population has been growing at a rate of 2.2% from 2000 to 2010. Its population increased from 192,157 to 238,300 in ten years.

B. Here we will examine the population decline of Detroit, Michigan over a period of ten years: 2000 to 2010.
Population in 2000: 951,307
Population in 2010: 713,777
We know from our investigation that N(t)=713777, N_{0} =951307, and t=10. Just like before, lets replace those values into our equation to find r:
713777=951307e^{10r}
e^{10r} = \frac{713777}{951307}
ln(e^{10r} )=ln( \frac{713777}{951307} )
r= \frac{ln( \frac{713777}{951307}) }{10}
r=-0.029
(-0.029)(100)= -2.9%.
We just show that Detroit's population has been declining at a rate of 2.2% from 2000 to 2010. Its population increased from 192,157 to 238,300 in ten years.

C. Final equation from point A: N(t)=192157e^{0.022t}.
Final equation from point B: N(t)=951307e^{-0.029t}
Similarities: Both have an initial population and use the same Euler's constant.
Differences: In the equation from point A the exponent is positive, which means that the function is growing; whereas, in equation from point B the exponent is negative, which means that the functions is decaying.

D. To find the year in which the population of Orlando will exceed the population of Detroit, we are going equate both equations N(t)=192157e^{0.022t} and N(t)=951307e^{-0.029t} and solve for t:
192157e^{0.022t} =951307e^{-0.029t}
\frac{192157e^{0.022t} }{951307e^{-0.029t} } =1
e^{0.051t} = \frac{951307}{192157}
ln(e^{0.051t})=ln( \frac{951307}{192157})
t= \frac{ln( \frac{951307}{192157}) }{0.051}
t=31.36
We can conclude that if Orlando's population keeps growing at the same rate and Detroit's keeps declining at the same rate, after 31.36 years in May of 2031 Orlando's population will surpass Detroit's population.

E. Since we know that the population of Detroit as 2000 is 951307, twice that population will be 2(951307)=1902614. Now we can rewrite our equation as: N(t)=1902614e^{-0.029t}. The last thing we need to do is equate our Orlando's population growth equation with this new one and solve for t:
192157e^{0.022t} =1902614e^{-0.029t}
\frac{192157e^{0.022t} }{1902614e^{-0.029t} } =1
e^{0.051t} = \frac{1902614}{192157}
ln(e^{0.051t} )=ln( \frac{1902614}{192157} )
t= \frac{ln( \frac{1902614}{192157}) }{0.051}
t=44.95
We can conclude that after 45 years in 2045 the population of Orlando will exceed twice the population of Detroit. 

  
8 0
3 years ago
larry,mary and terry each had a full glass of juice. larry drank 3/4 of his mary drank 3/8 of hers larry drank 3/4 of his terry
Katena32 [7]
3/4 is greater than 1/2

7/10 is greater than 5/10

and 3/8 is less the 4/8 (4/8=1/2)
3 0
3 years ago
Please help with these 3 questions and show all work!
Bas_tet [7]
Question 1:
"Match" the letters
DE are the last two letters of BCDE
The last two letters of OPQR is QR
DE is congruent to QR

Question 2:
Blank 3: Reflexive property (shared side)
Blank 4: SSS congruence of triangles (We have 3 sets of congruent sides)

Question 3:
I'm guessing those two numbers are 7.
Since both are 7, AB and AE are congruent.
We know that all the other sides are congruent because it is given.
We also know that there is a congruent angle in each triangle.
Thus, the two triangles are congruent by SAS or SSS.
(Note: I couldn't prove this without the two "7"s because there is no such thing as SSA congruence)

Have an awesome day! :)

8 0
3 years ago
What is 341/1000 in words
vladimir1956 [14]
Three-forty one over one thousand XD
7 0
3 years ago
B<br>Find all the missing angles - a,b,c, and d​
mart [117]

a=65° d=75° b=25° c=25°

4 0
2 years ago
Read 2 more answers
Other questions:
  • Mike has a stack of 10 cards numbered 1 to 10 if he randomly chooses two cards without replacing the first one drawn what is the
    13·2 answers
  • What is the percent of change from 56 to 22? round to the nearest percent
    5·1 answer
  • 1. (2,7); m=-4<br> What’s the answer?
    15·1 answer
  • Two central angles are listed below.
    5·1 answer
  • 42/15•3/7<br> need help multiplying this
    12·1 answer
  • Round 637.892 to whole number
    10·2 answers
  • (13.01 LC) What is the value of the expression 7 +(16 - 7) = 3 + 8? (2 points) O 12 O 15 O 17 O 18 Question 3​
    9·1 answer
  • Question 5 of 10<br> Which of the following is most likely the next step in the series?<br> CO
    12·2 answers
  • Kane is training for a marathon. He starts by running 3 miles during every training session. Each week plans to increase the dis
    7·1 answer
  • How does a sequence of translations, reflections, and rotations result in congruent figures?
    5·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!