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lapo4ka [179]
3 years ago
8

Which equation represents the hyperbola (y -2)^2/4 - (x-2)^2/9=1 in general form?

Mathematics
1 answer:
Ira Lisetskai [31]3 years ago
5 0

Answer:

9y^2-4x^2-36y+16x-16=0

Step-by-step explanation:

The given hyperbola has equation:

\frac{(y-2)^2}{4}-\frac{(x-2)^2}{9}=1

We multiply through by 36 to get:

9(y-2)^2-4(x-2)^2=36

We expand to get:

9(y^2-4y+4)-4(x^2-4x+4)=36

9y^2-36y+36-4x^2+16x-16=36

9y^2-36y-4x^2+16x-16=0

The equation of the hyperbola in general form is:

9y^2-4x^2-36y+16x-16=0

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