0.2(d-b)=0.3b+5-3+0.1d
you first distribute the 0.2 to the d and b in the parentheses, you'll then get
0.2d-0.2b=0.3b+5-3+0.1d
now you make sure that the b variables are with each other on the same side of the equal sign. so you subtract 0.3b from both sides to get
0.2d-0.5b=5-3+0.1d
now do the same thing with the d variables so subtract 0.1d from both sides to get
0.1d-0.5b=5-3
now you can subtract 5-3 which is easy to get
0.1d-0.5b=2
now you have to figure out what d and b equal. so i'll do b first. all you do is use the equation you have now and pretend that d is 0 so substitute the 0 in with the d variable to get
0.1(0)-0.5b=2
now you divide -0.5b from both sides to get
-0.5b/-0.5= b 2/-0.5= -4
so now you know b = -4
now you do sthe sane thing with b substitute with a 0 to get
0.1d-0.5(0)=2
then divide 0.1d from both sides to get
0.1d/0.1=b 2/0.1=20
now you know d = 20
( d=20, b=-4 )
I think that Neil has 12, Otto has 3 and Peter has 10.
2x + 6y = 20
3x - 2y = 8
I'll just substitute x and y with its corresponding values per option.
A) x = 4 ; y = 2
2(4) + 6(2) = 20 3(4) - 2(2) = 8
8 + 12 = 20 12 - 4 = 8
20 = 20 8 = 8
B) x = 4 ; y = -2
2(4) + 6(-2) = 20
8 - 12 = 20
-4 ≠ 20
C) x = -2 ; y = 4
2(-2) + 6(4) = 20 3(-2) - 2(4) = 8
-4 + 24 = 20 -6 - 8 = 8
20 = 20 - 14 ≠ 8
D) x = 2 ; y = 4
2(2) + 6(4) = 20
4 + 24 = 20
28 ≠ 20
Choice A. x = 4 ; y = 2 is the correct answer.
I think the answer is 50" because if the table is 42" and it needs to hang over 8" then it would have to be 50"
Answer: The original price of brownie was $2.1 each.
Step-by-step explanation:
since we have given that
Let the original price will be x
Number of brownie purchased = 8
According to question , each brownie costs $0.20 less than the original price.
So, it becomes
![8\times (x-0.20)=\$15.20\\\\8x-1.6=15.20\\\\8x=15.20+1.60\\\\8x=16.8\\\\x=\frac{16.8}{8}\\\\x=\$2.1](https://tex.z-dn.net/?f=8%5Ctimes%20%28x-0.20%29%3D%5C%2415.20%5C%5C%5C%5C8x-1.6%3D15.20%5C%5C%5C%5C8x%3D15.20%2B1.60%5C%5C%5C%5C8x%3D16.8%5C%5C%5C%5Cx%3D%5Cfrac%7B16.8%7D%7B8%7D%5C%5C%5C%5Cx%3D%5C%242.1)
Hence, the original price of brownie was $2.1 each.