Hello there, to answer your question...
258, percentage increased by 43% (percent) of its value
<h2>
= 368.94</h2>
<em>258 + 43% = 368.94</em>
<em></em>
I hope this information helps.
Answer:
![(x^\frac{3}{8})^\frac{3}{4} = \sqrt[32]{x^9}](https://tex.z-dn.net/?f=%28x%5E%5Cfrac%7B3%7D%7B8%7D%29%5E%5Cfrac%7B3%7D%7B4%7D%20%20%3D%20%5Csqrt%5B32%5D%7Bx%5E9%7D)
Step-by-step explanation:
Given
Required
Convert to radical form
Evaluate the exponents
Split the exponent
Apply the following law of indices
![(x^a)^\frac{1}{b} = \sqrt[b]{x^a}](https://tex.z-dn.net/?f=%28x%5Ea%29%5E%5Cfrac%7B1%7D%7Bb%7D%20%3D%20%5Csqrt%5Bb%5D%7Bx%5Ea%7D)
So, we have:
Answer:
x₂ = 7.9156
Step-by-step explanation:
Given the function ln(x)=10-x with initial value x₀ = 9, we are to find the second approximation value x₂ using the Newton's method. According to Newtons method xₙ₊₁ = xₙ - f(xₙ)/f'(xₙ)
If f(x) = ln(x)+x-10
f'(x) = 1/x + 1
f(9) = ln9+9-10
f(9) = ln9- 1
f(9) = 2.1972 - 1
f(9) = 1.1972
f'(9) = 1/9 + 1
f'(9) = 10/9
f'(9) = 1.1111
x₁ = x₀ - f(x₀)/f'(x₀)
x₁ = 9 - 1.1972/1.1111
x₁ = 9 - 1.0775
x₁ = 7.9225
x₂ = x₁ - f(x₁)/f'(x₁)
x₂ = 7.9225 - f(7.9225)/f'(7.9225)
f(7.9225) = ln7.9225 + 7.9225 -10
f(7.9225) = 2.0697 + 7.9225 -10
f(7.9225) = 0.0078
f'(7.9225) = 1/7.9225 + 1
f'(7.9225) = 0.1262+1
f'(7.9225) = 1.1262
x₂ = 7.9225 - 0.0078/1.1262
x₂ = 7.9225 - 0.006926
x₂ = 7.9156
<em>Hence the approximate value of x₂ is 7.9156</em>
Answer:
y =20 x + 25 (answer B in the list of options)
Step-by-step explanation:
y = 25 + 20 x = 20 x + 25
being 25 the flat fee and 20 the price per bottle
