Answer:\bf ~\hspace{7em}\textit{negative exponents} \\\\ a^{-n} \implies \cfrac{1}{a^n} ~\hspace{4.5em} a^n\implies \cfrac{1}{a^{-n}} ~\hspace{4.5em} \cfrac{a^n}{a^m}\implies a^na^{-m}\implies a^{n-m} \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ \left( 5^{\frac{3}{2}} \right)^{-\frac{2}{3}}\implies 5^{-\frac{3}{2}\cdot \frac{2}{3}}\implies 5^{-1}\implies \cfrac{1}{5}\implies 0.2 \\\\[-0.35em] ~\dotfill
\bf (256^{0.5})^{1.25}\implies [(2^8)^{0.5}]^{1.25}\implies [2^{8\cdot 0.5}]^{1.25}\implies [2^4]^{1.25}\implies 2^{4\cdot 1.25} \\\\\\ 2^5\implies 32 \\\\[-0.35em] ~\dotfill\\\\ ( 81^{-\frac{1}{6}} )^{\frac{3}{2}}\implies [(3^4)^{-\frac{1}{6}} ]^{\frac{3}{2}}\implies 3^{4\cdot -\frac{1}{6}\cdot \frac{3}{2}}\implies 3^{-\frac{12}{12}}\implies 3^{-1} \\\\\\ \cfrac{1}{3}\implies 0.33...
Step-by-step explanation: I don’t really know about inequalities can y’all help?
Answer:
Option (D)
Step-by-step explanation:
Endpoints of the sides of any polygon are called as vertices. Any polygon is named by its vertices either in a consecutive order either clockwise or counterclockwise.
In the picture attached,
Vertices of the triangle or endpoints of the sides of the polygon are A, T and X.
Therefore, we can name this triangle as ΔATX, ΔTXA, ΔXAT or ΔXTA, ΔAXT, ΔTAX.
Option (D) will be the answer.
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Answer:
love ya hey cry pokerface
Step-by-step explanation:
