Given:
Four different positive intergers as a product of 110
To find:
The sumnof the four numbers whose product is 110
Solution:
1) To find the number we have to find the prime factorization of the given number 110
2) Prime factorization of 110 is
110 = 1×2 × 5 = 11
3) So the four numbers whose product is 110 are 1,2,5 and 11
4) The sum of number's are
1+2+5+11=19
<h2>SO THE FINAL ANSWER IS 19</h2>
Answer: A=-2
Step-by-step explanation:
AB=11
B=9
B-11=A
9-11=A
A=-2