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andrezito [222]
3 years ago
5

Multiply and simplify.

Mathematics
1 answer:
Shkiper50 [21]3 years ago
3 0
1)
2•5(3)√9y2 (3)√3y

2) 3xy

3) 2√3
----------
3 ( like a fraction )
Decimal : 1.15
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Evaluate the given expression if x = 25, y = 10, w = 11, and z = 18.<br><br> (see the image)
hammer [34]

Answer:

D

Step-by-step explanation:

So we have the expression:

(x-y)^2+10wz

And we want to evaluate it when x=25, y=10, w=11, and z=18.

So, substitute these values for the variables:

=(25-10)^2+10(11)(18)

First, subtract within the parentheses:

=(15)^2+10(11)(18)

Square 15:

=225+10(11)(18)

Now, multiply the terms on the right. 10 times 11 is 110:

=225+110(18)

Multiply:

=225+1980

Finally, add:

=2205

So, our answer is D.

And we're done!

8 0
3 years ago
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Write an algebraic expression to represent the following verbal expression
DaniilM [7]
The answer is B. They are saying to cube the difference therefore you have (x-43) cubed
4 0
3 years ago
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Mike began with $20 in savings and increased his savings by $10 every month. Lindsay began with $5 in savings and doubled her sa
MrMuchimi

Answer:

Lindsay...................................

3 0
3 years ago
<img src="https://tex.z-dn.net/?f=%20%5Csqrt%7B125%20%7D%20-%20%5Csqrt%7B180%7D%20%2B%20%5Csqrt%7B45%7D%20" id="TexFormula1" tit
Kobotan [32]

Answer:

2\sqrt{5}

Step-by-step explanation:

Using the rule of radicals

\sqrt{a} × \sqrt{b} ⇔ \sqrt{ab}

Simplifying the radicals

\sqrt{125} = \sqrt{25(5)} = \sqrt{25} × \sqrt{5} = 5\sqrt{5}

\sqrt{180} = \sqrt{36(5)} = \sqrt{36} × \sqrt{5} = 6\sqrt{5}

\sqrt{45} = \sqrt{9(5)} = \sqrt{9} × \sqrt{5} = 3\sqrt{5}

Thus

\sqrt{125} - \sqrt{180} +\sqrt{45}

= 5\sqrt{5} - 6\sqrt{5} + 3\sqrt{5}

= 2\sqrt{5}

3 0
3 years ago
How do i solve this rational expression r-4/5r=1/5r+1
NNADVOKAT [17]

r - 4/5r  =  1/5r + 1

Subtract  1/5r from each side:    r - 4/5r - 1/5r  =  1

Combine all the 'r' terms on the left side: 

                                 r - 5/5r  =  1

                                 r  -  r  =  1

                                       0  =  1

There is no value of 'r' that can make ' 0 = 1 ' a true statement.
So the equation has <em>no solution</em>.


4 0
3 years ago
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