Ask question

Ask question

All categories

3 years ago

8

What is the value of tan A?

1 answer:

Nookie1986 [14]3 years ago

7 0

TanA equals opp/hyp so 12/15 or 4/5

You might be interested in

Two adjacent supplementary angles form a

Sedbober [7]

Obtuse because it all adds up to 180 degrees <span />

4 0

3 years ago

Students played dodge ball and volleyball for 45 minutes. Thy played dodgeball for 11 more minutes than they played volleyball.

kirill115 [55]

28 minutes
45 - 11 divided by 2 = 17 + 11 = 28 minutesa

4 0

3 years ago

Read 2 more answers

You work a part-time job at $7.85/hr for 10 hours per week. Your deductions are FICA (7.65%), federal tax withholding (9.8%), an

Dmitrij [34]

Here, My initial salary = 7.85

FICA deduction amount = 7.85 * 7.65% = 7.85 * 0.0765 = 0.60
Federal Tax amount = 7.85 * 9.8% = 7.85 * 0.098 = 0.77
State tax amount = 7.85 * 5.5% = 7.85 * 0.055 = 0.43

So, Total deducted amount = 0.60 + 0.77 + 0.43 = 1.80
Net hourly wage = 7.85 - 1.80 = 6.05

In short, Your Answer would be $6.05

Hope this helps!

4 0

3 years ago

The miles-per-gallon rating of passenger cars is a normally distributed random variable with a mean of 33.8 mpg and a standard d

EleoNora [17]

Answer:

The probability that a randomly selected passenger car gets more than 37.3 mpg is 0.1587.

Step-by-step explanation:

Let the random variable <em>X</em> represent the miles-per-gallon rating of passenger cars.

It is provided that $X\sim N(\mu=33.8,\ \sigma^{2}=3.5^{2})$ .

Compute the probability that a randomly selected passenger car gets more than 37.3 mpg as follows:

$P(X>37.3)=P(\frac{X-\mu}{\sigma}>\frac{37.3-33.8}{3.5})$

$=P(Z>1)\\\\=1-P(Z$

Thus, the probability that a randomly selected passenger car gets more than 37.3 mpg is 0.1587.

7 0

3 years ago

I NEED HELP WITH A PROBLEM

Lapatulllka [165]

Answer:

39

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers