How do you write 7,380 in scientific notation

Which statements are true for verifying the solution set of StartAbsoluteValue negative 2 x + 8 EndAbsoluteValue less-than 12 as

mariarad [96]

Answer:

I had to go back and double check, this was kind of confusing asking if saying this statement is true or false is true or false. So keep your eye on that. as long as x is between (but not equal to) -2 and 10 then the inequality is true. Fromt here you have to see if the option is SAYING it is true or not.

Step-by-step explanation:

I am assuming this is saying |-2x+8|<12 as -2 < x < 10

Substituting 10 for x into the original inequality will create a false statement.

True, since x has to be explicitly LESS THAN 10, not equal

Substituting 6 for x into the original inequality will create a false statement.

False, 6 is greater than -2 and less than 10

Substituting 20 for x into the original inequality will create a true statement.

False, greater than 10

Substituting –20 for x into the original inequality will create a false statement.

True. Kinda confusing since it is asking if it is a false statement. It is TRUE that it is a false statement.

Substituting –10 for x into the original inequality will create a true statement.

False, x needs to be between -2 and 10 (explicitly between and not equal to) to be true.

Substituting 0 for x into the original inequality will create a true statement

True, it is between -2 and 10

8 0

3 years ago

Read 2 more answers

Let xy=1 and let dy/dt=5 Find dx/dt when x=5

madreJ [45]

So the first step is to take the derivative of xy=1. Don't forget the product chain rule!

 $xy=1
\\x=5
\\y= \frac{1}{x}=\frac{1}{5}
\\ 
\\\frac{dy}{dt}=5
\\
\\x\frac{dy}{dt}+y\frac{dx}{dt}=0
\\
\\5\times5+ \frac{1}{5} \frac{dx}{dt}=0
\\
\\\frac{1}{5} \frac{dx}{dt}=-25
\\
\\ \frac{dx}{dt}=-125
$

3 0

3 years ago

(4x^2+1)+(4x^2+x+2) what’s the sum ?

pochemuha

Answer:

$(4 {x}^{2} + 1) + (4 {x}^{2} + x + 2) \\ 4 {x}^{2} + 1 + 4 {x}^{2} + x + 2 \\ = 8 {x}^{2} + x + 3$