Answer: Km = 10μM
Explanation: <u>Michaelis-Menten constant</u> (Km) measures the affinity a enzyme has to its substrate, so it can be known how well an enzyme is suited to the substrate being used. To determine Km another value associated to an eznyme is important: <em>Turnover number (Kcat)</em>, which is the number of time an enzyme site converts substrate into product per unit time.
Enzyme veolcity is calculated as:
![V_{0} = \frac{E_{t}.K_{cat}.[substrate]}{K_{m}+[substrate]}](https://tex.z-dn.net/?f=V_%7B0%7D%20%3D%20%5Cfrac%7BE_%7Bt%7D.K_%7Bcat%7D.%5Bsubstrate%5D%7D%7BK_%7Bm%7D%2B%5Bsubstrate%5D%7D)
where Et is concentration of enzyme catalitic sites and has to have the same unit as velocity of enzyme, so Et = 20nM = 0.02μM;
To calculate Km:
![V_{0}*K_{m} + V_{0}*[substrate] = E_{t}.K_{cat}.[substrate]](https://tex.z-dn.net/?f=V_%7B0%7D%2AK_%7Bm%7D%20%2B%20V_%7B0%7D%2A%5Bsubstrate%5D%20%3D%20E_%7Bt%7D.K_%7Bcat%7D.%5Bsubstrate%5D)
![K_{m} = \frac{E_{t}.K_{cat}.[substrate]-V_{0}*[substrate]}{V_{0}}](https://tex.z-dn.net/?f=K_%7Bm%7D%20%3D%20%5Cfrac%7BE_%7Bt%7D.K_%7Bcat%7D.%5Bsubstrate%5D-V_%7B0%7D%2A%5Bsubstrate%5D%7D%7BV_%7B0%7D%7D)

Km = 10μM
<u>The Michaelis-Menten for the substrate SAD is </u><u>10μM</u><u>.</u>
<u>Answer: </u>The volume occupied by
at STP is 0.56 L.
<u>Explanation:</u>
To calculate the number of moles, we use the equation:

We are given:
Given mass of oxygen = 0.80 g
Molar mass of oxygen = 32 g/mol
Putting values in above equation, we get:

<u>At STP:</u>
1 mole of a gas occupies 22.4 L of volume.
So, 0.025 moles of oxygen gas will occupy =
of volume.
Hence, the volume occupied by
at STP is 0.56 L.
Answer: The activation energy is 10 kJ and the reaction is exothermic.
Explanation: Exothermic reactions are those in which heat is released and thus the energy of products is less than the energy of reactants.
Endothermic reactions are those in which heat is absorbed and thus the energy of products is more than the energy of reactants.
Activation energy is the extra amount of energy required by the reactants to cross the energy barrier to convert to products.
Given : Energy of reactants = 40kJ
Energy of activation: (50-40)=10 kJ
Energy of products = 50 kJ
Energy of products = 15 kJ
Thus Energy of products (15kJ) < Energy of reactants(40kJ), the reaction is exothermic as energy has been lost to surroundings in the form of heat.
Answer: Option (5) is the correct answer.
Explanation:
It is known that more is the number of carbon atoms linearly present in a compound more will be its boiling point. This is because then more number of intermolecular forces are present within the atoms of a compound.
Hence, lesser is the number of carbon atoms present less will be the intermolecular forces present in it. Therefore, more readily the compound will evaporate into the atmosphere.
Thus, we can conclude that given compounds are ranked in increasing rate of evaporation as follows.
< CH_{3}CH_{2}OH[/tex] < 