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2 years ago

Unrestricted populations of organisms experience _____.

Chemistry

2 answers:

Alik [6]2 years ago

6 0

Answer:

1. A

2. D

Explanation:

1. If a population is left unrestricted, meaning it is not limited to anything, then the population will continue to increase exponentially due to there being no limits.

2. If a population is limited, and it has reached its <u>carrying capacity</u>, then the essential needs of life are being competed for. Things like food, shelter, and mates are now a limited resource, and hence the option would be "all of the above".

Fudgin [204]2 years ago

5 0

Unrestricted populations of organisms experience Exponential growth.

As a population reaches is carrying capacity there is an increase in competition for All of the above.
Hope I helped.

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What is Cd2+ and F1- together as a formula

geniusboy [140]

Answer:

i am not sure tho

Explanation:

Cd ²+ + F¹- = CdF2

F fluor is a non metal so he takes the electons that Cd gives so if Vd has to give 2 electrons and F can take only 1, there has to be 2 F atoms so all the electrona can be neutral and in ionisation

4 0

3 years ago

hydrogen chloride, hydrogen nitrate (v), sodium chloride, sodium hydroxide. Name a substance known as common salt

trasher [3.6K]

Answer:

C: Sodium chloride

Explanation:

Common salt is gotten when sodium atoms reacts with chlorine atoms in an exothermic reaction to form an ionic substance known as sodium chloride with the chemical formula NaCl.

Equation is;

2Na + Cl2 = 2NaCl

Looking at the options, the correct one is Sodium chloride.

7 0

3 years ago

A) Calculate the average density of the following object (assume it is a perfect sphere). SHOW ALL YOUR WORK (formulas used, num

-BARSIC- [3]

Answers:

A) 2040 kg/m³; B) 58 600 km

Explanation:

A) Density

$V = \frac{ 4}{3 }\pi r^{3} = \frac{ 4}{3 }\pi\times (\text{1150 km})^{3} = 6.37 \times 10^{9} \text{ km}^{3}$

$\text{Density} = \frac{\text{mass}}{\text{volume}} = \frac{1.3\times 10^{22} \text{ kg} }{6.37 \times 10^{9} \text{ km}^{3}}\times (\frac{\text{1 km}}{\text{1000 m}})^{3} = \text{2040 kg/m}^{3}$

<em>B) Radius</em>

$\text{Volume} = \frac{\text{mass}}{\text{density}} = \frac{5.68\times 10^{26} \text{ kg} }{687 \text{ kg/m}^{3} }= 8.268 \times 10^{23} \text{ m}^{3}$

$V = \frac{ 4}{3 }\pi r^{3}$

$r^{3} = \frac{3V }{4 \pi }\$

$r= \sqrt [3]{ \frac{3V }{4 \pi } }$

$r= \sqrt [3]{ \frac{3\times 8.268 \times 10^{23} \text{ m}^{3}}{4 \pi } }= \sqrt [3]{ 1.974 \times 10^{23} \text{ m}^{3}}= 5.82 \times 10^{7} \text{ m}=\text{58 200 km}$