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topjm [15]
3 years ago
11

1.025 of 50 is what number?

Mathematics
2 answers:
makvit [3.9K]3 years ago
8 0
.............................................................................................................................

shtirl [24]3 years ago
6 0
0.5125

Mark me brainliest for more anwsers.

This is wrong, I did a typo.<span />
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39<br> 125°<br> Find the value of x
Savatey [412]

Answer:

Step-by-step explanation:

The sum of the interior angles of this triangle must be 180 degrees.

Thus, angle x is 180 degrees less (39 degrees plus 125 degrees), or

x = 180 degrees - 164 degrees = 16 degrees.

Because of the 125 degree angle, this is an obtuse triangle.

8 0
3 years ago
Solve<br> 3(2x - 5) = 9(10 - x)
alisha [4.7K]

Answer:

x=7

Step-by-step explanation:

3(2x - 5) = 9(10 - x)

6x-15=90-9x

6x+9x=90+15

15x=105

x=7

4 0
3 years ago
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A 8-foot tall man is standing beside a 32-foot flagpole. The flagpole is
kipiarov [429]

Answer:

The flagpole's shadow is 16.875 feet longer than the man's shadow

Step-by-step explanation:

The total length of the shadow is expressed by taking its actual length by a factor that depends on the position of the sun which is constant for the man too. The expression is as follows;

Height of the shadow=actual height of the flagpole×factor

where;

length of the flagpole's shadow=22.5 feet

actual height of the flagpole=32 feet

factor=f

replacing;

22.5=32×f

32 f=22.5

f=22.5/32

f=0.703125

Using this factor in the expression below;

Length of man's shadow=actual height of man×factor

where;

length of man's shadow=m

actual height of man=8 feet

factor=0.703125

replacing;

length of man's shadow=8×0.703125=5.625 feet

Determine how much longer the flagpole's shadow is as follows;

flagpoles shadow-man's shadow=22.5-5.625=16.875 feet

The flagpole's shadow is 16.875 feet longer than the man's shadow

7 0
3 years ago
When two geometric figures (angles, rectangles, etc.) have the same size and shape, they are called ____.
e-lub [12.9K]

When two geometric figures (angles, rectangles, etc.) have the same size and shape, they are called <u>Congruent.</u>

7 0
3 years ago
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Suppose that an insect population’s density, in thousands per acre, during year n, can be modeled by the recursive formula: a1 =
vlabodo [156]

Answer:

The population alternates between increasing and decreasing

Step-by-step explanation:

<u><em>The options of the question are</em></u>

A) The population density decreases each year.

B) The population density increases each year.

C) The population density remains constant.

D) The population alternates between increasing and decreasing

we have

a_n=2.9(a_n_-_1)-0.2(a_n_-_1)^2

a_1=8

Find the value of a_2

For n=2

a_2=2.9(a_1)-0.2(a_1)^2

a_2=2.9(8)-0.2(8)^2=10.4

Find the value of a_3

For n=3

a_3=2.9(a_2)-0.2(a_2)^2

a_3=2.9(10.4)-0.2(10.4)^2=8.528

For n=4

a_4=2.9(a_3)-0.2(a_3)^2

a_4=2.9(8.528)-0.2(8.528)^2=10.1858

For n=5

a_5=2.9(a_4)-0.2(a_4)^2

a_5=2.9(10.1858)-0.2(10.1858)^2=8.7887

therefore

The population alternates between increasing and decreasing

7 0
3 years ago
Read 2 more answers
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