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ycow [4]
3 years ago
9

Round 344,501 to the nearest 10,000

Mathematics
1 answer:
Luda [366]3 years ago
3 0

Answer:

Step-by-step explanation:

Round 344,501 to the nearest ten thousand

340000 to the nearest ten thousand

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7 + 7x - (2x) + 3 if x = -4
frutty [35]

Answer:

-10

Step-by-step explanation:

7 + 7(-4) - (2(-4)) + 3

7 - 28 - (-8)+3

7 - 28 +8 +3

= -10

4 0
2 years ago
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A video store charges
Juli2301 [7.4K]

Answer:

a. 10 + 2.50x

b. 60

c. 100

Step-by-step explanation:

a. 10 + 2.50x

b. 10 + 2.50(20)

= 10 + 50

= 60

c. 260 = 10 + 2.50x

250 = 2.50x

250/2.50 = x

x = 100

8 0
3 years ago
I NEED YALL’S HELP <br> 2x+12=64<br> Step by step
OverLord2011 [107]

Answer:

2x + 12 = 64

x = 26 (mark brain if this helps and is correct)

Step-by-step explanation:

to solve equations with one missing variable we must use the order of operations of equality

step 1: use the subtraction property of equality meaning subtract each side of the equation

ex: 2x + 12 - 12 = 64 - 12   (2x = 52)

step 2: use the division property of equality meaning divide each side of the equation by 2

ex: 2x/2 = 52/2   (x = 26)

step 3: check your answer by putting 26 as x because that is our answer

2(26) + 12 = 64 (multiply 2 * 26)

52 + 12 = 64 (add 52 + 12)

64 = 64 (if both sides of the equation are the same number like 64 = 64 then your answer is true meaning that x is equal to 26)

8 0
3 years ago
Please help me. I dont have much time! Thank you if you decide to help tho​
nadya68 [22]
It would either be C or D I think.
6 0
3 years ago
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Perform the indicated operation. x/x + 1 - 1/x - 1 + 2x/x^2 - 1 =
luda_lava [24]
\frac{x}{x + 1} - \frac{1}{x - 1} + \frac{2x}{x^{2} - 1}
\frac{x}{x + 1} - \frac{1}{x - 1} + \frac{2x}{(x + 1)(x - 1)}
\frac{x(x - 1)}{(x + 1)(x - 1)} - \frac{1(x + 1)}{(x + 1)(x - 1)} + \frac{2x}{(x + 1)(x - 1)}
\frac{x^{2} - x}{(x + 1)(x - 1)} - \frac{x + 1}{(x + 1)(x - 1)} + \frac{2x}{(x + 1)(x - 1)}
\frac{x^{2} - x + x + 1 + 2x}{(x + 1)(x - 1)}
\frac{x^{2} + 2x + 1}{(x + 1)(x - 1)}
\frac{(x + 1)(x + 1)}{(x + 1)(x - 1)}
\frac{(x + 1)^{2}}{(x + 1)(x - 1)}
\frac{x + 1}{x - 1}
4 0
3 years ago
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