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Alex Ar [27]
3 years ago
12

1296 ÷ 48 help me please

Mathematics
2 answers:
Nataly_w [17]3 years ago
8 0
Answer is 27. 48 goes into 1295 that many times; just take your time.
Elan Coil [88]3 years ago
7 0
The answer in 27 $$$$$$$$$$$$$$$$$$$$$$$$
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PLEASE ANSWER!!!!! THXXX SM IF U DO!
Phoenix [80]
He had x + 3 gallons of water

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So the answer = (x + 3)/4
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3 years ago
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Write the equation of the circle in general form. Show all of your work
finlep [7]
<h2>1. What are the center and equation of the circle?</h2>

In this exercise we have the general form of the equation of a circle, which is given by:

x^2+y^2+18x+4y+49=0

The ordinary equation of a circle is:

(x-h)^2+(y-k)^2=r^2 \\ \\ Developing \ this \ equation: \\ \\ x^2+y^2-2hk-2ky+h^2+k^2-r^2=0

But this can be written as:

x^2+y^2+Dx+Ey+F=0 \\ \\ D=-2h, \ E=-2k, \ and \ F=h^2+k^2-r^2

From the original equation we know that:

D=18, \ E=4, \ and \ F=49 \\ \\ So: \\ \\ h=-\frac{18}{2}=9, \ k=-\frac{4}{2}=2, \ and \ r=\sqrt{9^2+2^2-49}=6

Finally:

\boxed{CENTER: \ (h,k)=(9,2)} \\ \\ \boxed{RADIUS: \ 6}

<h2>2. Write the equation of the circle in general form.</h2>

We need to write this equation in the form:

x^2+y^2+Dx+Ey+F=0

Since:

D=-2h, \ E=-2k, \ and \ F=h^2+k^2-r^2

Then we need to find the center and radius in order to get D, E and F then. From the graph, it is easy to know that the center is (h,k)=(-3,4) and the radius is 2. Therefore:

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\boxed{x^2+y^2+6x-8y+21=0}

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(y-k)^2=4p(x-h) \ \ p \neq 0

The vertex is (h,k)=(-5,8) so our goal is to find p:

(y-8)^2=4p(x+5)

We can find the absolute value of p as follows:

\left|p\right|=2-(-5)=7

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p.

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(y-8)^2=4(-7)(x+5) \\ \\ \boxed{(y-8)^2=-28(x+5)}

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Neporo4naja [7]
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