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Minchanka [31]
3 years ago
7

Simplify the expression ASAP 8p3

Mathematics
1 answer:
Reika [66]3 years ago
5 0

Answer:

336

Step-by-step explanation:

8P3

=8!(8-3)!

=8!5!

=8x7x6

=336

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Select all statements that are true about the graph of ordered pair (5, −1) . The point is 5 units below the x-axis. The point i
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The -1 means that y = -1, so point is one unit below the x-axis.  In (5, -1), the x is positive, which could put the point in either the first quadrant or the fourth.  With the y being negative, however, it means that the point is in the fourth quadrant.  Those are your 2 true statements.
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A movie cost $3,254,107 to produce. Which digit is in the hundred thousand place
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2 is in the hundred thousands place
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Stacey had 3 cakes for her party, She had 1/8 of a cake left after the party. How much cake was eaten at her party?​
hoa [83]

Answer: 3=24/8 24/8 - 1/8 = 23/8 or 2 7/8

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A donut store has 11 different types of donuts. You can only buy a bag of 3 of them, where each donut has to be of a different t
MakcuM [25]

Answer:

165.

Step-by-step explanation:

Since repetition isn't allowed, there would be 11 choices for the first donut, (11 - 1) = 10 choices for the second donut, and (11 - 2) = 9 choices for the third donut. If the order in which donuts are placed in the bag matters, there would be 11 \times 10 \times 9 unique ways to choose a bag of these donuts.

In practice, donuts in the bag are mixed, and the ordering of donuts doesn't matter. The same way of counting would then count every possible mix of three donuts type 3 \times 2 \times 1 = 6 times.

For example, if a bag includes donut of type x, y, and z, the count 11 \times 10 \times 9 would include the following 3 \times 2 \times 1 arrangements:

  • xyz.
  • xzy.
  • yxz.
  • yzx.
  • zxy.
  • zyx.

Thus, when the order of donuts in the bag doesn't matter, it would be necessary to divide the count 11 \times 10 \times 9 by 3 \times 2 \times 1 = 6 to find the actual number of donut combinations:

\begin{aligned} \frac{11 \times 10 \times 9}{3 \times 2 \times 1} = 165\end{aligned}.

Using combinatorics notations, the answer to this question is the same as the number of ways to choose an unordered set of 3 objects from a set of 11 distinct objects:

\begin{aligned}\begin{pmatrix}11 \\ 3\end{pmatrix} &= \frac{11 !}{(11 - 3)! \times 3 !} \\ &= \frac{11 !}{8 ! \times 3 !} \\ &= \frac{11 \times 10 \times 9}{3 \times 2 \times 1} = 165\end{aligned}.

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2 years ago
4.82 <br> write as a fraction or mixed number in simplest form
Dima020 [189]

I'm pretty sure 4.82 as a simplified fraction is 241/50.

6 0
3 years ago
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