Question

Which is a zero od the quadratic function f(x)=16x²+32x-9?

Answer 1

Olá!

$\left[\begin{array}{ccc}\Delta=b^2-4.ac\\ \\ x=\frac{-b\±\sqrt{\Delta}}{2.a}\end{array}\right]$

a = 16
b = 32
c = -9

$\Delta$ = 32² - 4.16. (- 9)
$\Delta$ = 1024 - (- 576)
$\Delta$ = 1600

$x'=\frac{-(32)+\sqrt{1600}}{2.16}=\frac{-(32)+40}{32}=\frac{8}{32}=0.25\\ \\ \\ x'' =\frac{-(32)-\sqrt{1600}}{2.16}=\frac{-(32)-40}{32}=\frac{-72}{32}=-2.25$