By knowing that <em>water</em> outflow is <em>stable</em> and the known geometry, the <em>draining</em> time of the rectangular tank is equal to a time of a minute and 36 seconds.
<h3>How to determine the draining time of a rectangular tank</h3>
In this question we must determine the <em>draining</em> time of a tank whose dimensions are known and whose <em>water</em> outflow is <em>stable</em>. The <em>draining</em> time is equal to the volume of the <em>rectangular</em> tank divided by <em>outflow</em> rate:
V = (1.2 m) · (0.8 m) · (0.5 m)/(0.3 m³/min)
V = 1.6 min
By knowing that <em>water</em> outflow is <em>stable</em> and the known geometry, the <em>draining</em> time of the rectangular tank is equal to a time of a minute and 36 seconds.
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Disance between (x1,y1) and (x2,y2) is
given (-2,5) (3,-4)
D=√106
the distance is √106 units or abotu 10.2
Answer:
V=1884 Cubic mm
Step-by-step explanation:
We know that the volume of the Sphere is given by the formula
Where r is the radius and h is the height of the cylinder
We are asked to determine the radius of the hollow cylinder , which will be the difference of the solid cylinder and the cylinder being carved out.
Where
is the the volume of solid cylinder with radius and height h
is the volume of the cylinder being carved out with radius and height h
where
mm ( Half of the bigger diameter )
mm ( Half of the inner diameter )
mm
Putting these values in the formula for V we get
Answer:
5
Step-by-step explanation:
If cos(70) = 0.342
the cosine of the alternative angle of 70° will also give the same value
angle measure = 360 - 70 = 240°
cos (240) will also be 0.342