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3 years ago

Is the point (−4,−17) a solution to the inequality 2y−3x>12?

Mathematics

1 answer:

Arturiano [62]3 years ago

4 0

substitute the values for the letters

2(-17) = -34

3(-4) = -12

-34 - -12 = -34 +12 = -22

-22 is not greater than 12 so it is not a solution

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Help!! Answer !!! about to run out of time in test!!

Gemiola [76]

$\qquad \qquad\huge \underline{\boxed{\sf Answer}}$

Here's the solution ~

Let's find the measure of hypotenuse first, by using Pythagoras theorem ;

$\qquad \sf \dashrightarrow \: h {}^{2} = {8}^{2} + {6}^{2}$

$\qquad \sf \dashrightarrow \: h {}^{2} = {36}^{} + {64}^{}$

$\qquad \sf \dashrightarrow \: h {}^{2} = 100$

$\qquad \sf \dashrightarrow \: h {}^{} = \sqrt{100}$

$\qquad \sf \dashrightarrow \: h {}^{} = {10}$

Now, let's find the asked values ~

$\qquad \sf \dashrightarrow \: \sin(x) = \dfrac{opposite \: side}{hypotenuse}$

$\qquad \sf \dashrightarrow \: \sin(x) = \dfrac{6}{10}$

$\qquad \sf \dashrightarrow \: \sin(x) = \dfrac{3}{5} \: or \: 0.6 \: units$

For Cos y :

$\qquad \sf \dashrightarrow \: \cos(y) = \dfrac{adjcant \: side}{hypotenuse}$

$\qquad \sf \dashrightarrow \: \cos(y) = \dfrac{6}{10}$

$\qquad \sf \dashrightarrow \: \cos(y) = \dfrac{3}{5} \: or \: 0.6 \: units$

As we can see that both sin x and Cos y have equal values, therefore The required relationships is equality.

I.e Sin x = Cos y

Hope it helps ~

3 0

3 years ago

What is3/4 - 1/2 and what is 7/8-2/3

Mariulka [41]

3/4 - 1/2 = 3/4 - 2/4 = 1/4

7/8 - 2/3 = 21/24 - 16/24 = 5/24

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3 years ago

-9 +m=20<br> answer asap please!!

grigory [225]

Answer:

Step-by-step explanation:

at 9 on both sides to get m alone

-9+m=20

+9. +9

m= 29

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Gnesinka [82]

Answer:

-1 Your answer is A

Step-by-step explanation:

4+ 10/-2=-1

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3 years ago

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True or False, the below is a right triangle: a = 14, b = 16, c =18

Lisa [10]

Answer:

true

Step-by-step explanation:

this is true because you have to solve each equation and then u get your answer

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