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3 years ago

Is the number 147 prime or composite? Explain how you know.

Mathematics

2 answers:

Lorico [155]3 years ago

7 0

Composite because it ends in 7

Ilia_Sergeevich [38]3 years ago

7 0

147 is not a prime number because it can't be divisible by itself or one.

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What is the mean of the data set? 17, 24, 26, 13 4 13 20 80

a_sh-v [17]

Answer:

Step-by-step explanation:

You need to add all four then divide the answer by 4.

Hope this helps.

6 0

3 years ago

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PLEASE HELP Complete the table with the number of sit-ups you have to do sunday so that the mean number of sit-ups per day is 10

klemol [59]

The complete table will be:

$Monday - 100\\ Tuesday-65\\ Wednesday- 120\\ Thursday-150\\ Friday-90\\ Saturday- 0\\ Sunday-175$

Explanation

Suppose, the number of sit-ups in Sunday is $x$

Mean is the simple average of some numbers. For finding the mean number of sit-ups per day, we need to divide the 'total number of sit-ups' by the 'total number of days'.

Here the total number of days is 7 and the total number of sit-ups for 7 days $= 100+65+120+150+90+0+x= 525+x$

Given that, the mean number of sit-ups per day is 100. So, the equation will be...

$\frac{525+x}{7}=100\\ \\ 525+x=700\\ \\ x= 700-525=175$

So, the number of sit-ups you have to do Sunday is 175.

6 0

3 years ago

The lcm of 2 numbers is 60 and one of the numbers is 7 less than the other number

brilliants [131]

The two numbers are 5 and 12.

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3 years ago

The rate of growth of profit (in millions) from an invention is approximated by Upper P prime (x )equals x e Superscript negati

Alecsey [184]

Answer:

The function is $P(x) = \frac{1}{2} e^{-x^2} +0.016$

Step-by-step explanation:

From the question we are told that

The rate of growth is $P'(x) = xe^{x} - x^2$

The total profit is $P(2) =$ $25,000

The time taken to make the profit is $x = 2 \ years$

From the question

$P'(x) = xe^{-x^2}$ is the rate of growth

Now here x represent the time taken

Now the total profit is mathematically represented as

$P(x) = \int\limits {P'(x)} \, = \int\limits {xe^{-x^2}} \,$

So using substitution method

We have that

$u = - x^2$

$du = 2xdx$

$p(x) = \int\limits {\frac{1}{2} e^{-u}} \, du$

$p(x) = {\frac{1}{2} [ e^{-u}} +c ]$

$p(x) = {\frac{1}{2} e^{-x^2}} + \frac{1}{2} c$ recall $u = - x^2$ and let $\frac{1}{2} c = Z$

At x = 2 years

$P(x) =$ $25,000

Since the profit rate is in million

$P(x) =$ $25,000 = $\frac{25000}{1000000} =$ $0.025 millon dollars

$0.025 = {\frac{1}{2} e^{-2^2}} + Z$

=> $Z = 0.025 - {\frac{1}{2} e^{-2^2}}$

$Z = 0.016$

So the profit function becomes

$P(x) = \frac{1}{2} e^{-x^2} +0.016$

5 0

3 years ago

Help please uh thanks

Triss [41]

12•1
13•6
12/78 divide both numbers by 6 to simplify
Answer- 2/13

6 0

2 years ago

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