Given :
An expression (cos 6m)(cos 2m) .
To Find :
We need to express it in terms as sum or difference.
Solution :
We know,
cos( A + B ) = cosA cos B - sin A sin B
cos( A - B ) = cosA cos B + sin A sin B
Adding both the equations we get :
2cos A cos B = cos( A + B) + cos( A - B )
or
cos A cos B = cos( A + B) + cos( A - B )/2
Putting value of A = 6m and B = 2m in above equation, we get :
(cos 6m)(cos 2m) = cos( 6m + 2m ) + cos( 6m - 2m )/2
(cos 6m)(cos 2m) = cos(8m) + cos(4m)/2
Hence, this is the required solution.
Answer:
i dont think you can solve this because
The expression is not factorable with rational numbers.
there are no like terms
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Answer:
The first number in each ordered pair tells how far across the X line is to move. The second number in each ordered pair tells how far up or down the Y line is to move. The point where the X and Y lines cross is marked “0” on the graph. It is called the “origin,” and is the starting point for plotting points.
Answer: Your picture is blocked.
Step-by-step explanation:
