Question

Let f(x) = 12x5 − 36x4 − 6x3 and g(x) = 3x2. Find f of x over g of x.

Answer 1

Answer:

$4x^3-12x^2-2x$

Step-by-step explanation:

Given:

$f(x)= 12x^5-36x^4-6x^3$

$g(x)=3x^2$

We need to find  $\frac{f(x)}{g(x)}$ .

Solution:

We have attached the division for your reference.

Step 1:

Now here Dividend is $12x^5-36x^4-6x^3$ and Divisor is $3x^2$ so we will multiply the Divisor with $4x^3$ we will get the answer as $12x^5$ so from dividend $12x^5$  will get subtracted and the remainder will be $-36x^4-6x^3$ and the Quotient will be $4x^3$.

Step 2:

Now the Dividend is $-36x^4-6x^3$ and Divisor is $3x^2$ so we will multiply the Divisor with $-12x^2$ we will get the answer as $-36x^2$ so from dividend $-36x^2$will get subtracted and the remainder will be $-6x^3$ and the Quotient will be $4x^3-12x^2$

Step 3:

Now the Dividend is $-6x^3$ and Divisor is $3x^2$ so we will multiply the Divisor with $-2x$ we will get the answer as so $-6x^3$ from dividend $-36x^2$will get subtracted and the remainder will be 0 and the Quotient will be $4x^3-12x^2-2x$

Hence $\frac{f(x)}{g(x)} =4x^3-12x^2-2x$.

Answer 2

Answer: 4x^3-12x^2-2x

Step-by-step explanation:

Given:

Step-by-step explanation: